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Irina-Kira [14]
3 years ago
9

A 171 g sample of tetrafluoromethane (CF4) contains 90 g of carbon. What is the mass percent of fluorine in the compound?

Chemistry
2 answers:
inn [45]3 years ago
8 0
<span>To find the mass percent of fluorine in the compound, you must first determine the mass in g of fluorine in the compound. We do this by subtracting the mass of carbon from the total mass of the sample. From this we get 171 - 90 = 81g of fluorine in CF4 sample. Now to get the mass percent, we divide the fluorine mass by the sample mass to get the percent mass. 81/171 = .4737 which multiplied by 100 to get percentage give 47.37%.</span>
rodikova [14]3 years ago
8 0
<span>Mass of fluorine:171 g (compound ) - 90 ( carbon )  =>  81 g of

fluorinepercent of fluorine in the compound:

( 81 g F ) / 171 ( compound ) x  100 %

= 0,4737 x 100 = 47,37%

hope this helps!</span>
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A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
Anestetic [448]

Answer:

mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

m = 10 - 2m

3m = 10

m = 10/3

m = 3.33 g of X

Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

8 0
3 years ago
Which quantity is equivalent to the product of the absolute index of refraction of water and the speed of light in water?
givi [52]

The quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

<h3>What is the speed of light?</h3>

Speed of light is the rate of speed though the light travels. To find the speed of light in any medium, the following formula is used.

v=\dfrac{c}{n}

Here, (n) is the index of reaction and (c) is the speed of light in the vacuum. The speed of light in the vacuum is almost equal to the 3.0×10⁸ m/s.

Now the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water has to be find out.

The above formula can be written as,

v=\dfrac{c}{n}\\vn=c\\c=vn

Here, the product of index of refraction and speed of light is equal to the speed of light in vacuum. This will be true for water as well.

Thus, the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

Learn more about the speed of light here;

brainly.com/question/104425

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3 0
2 years ago
Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat
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In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.

If heat is absorbed in a reaction, that reaction is endothermic.

Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.

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Answer: The answer is B

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