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Irina-Kira [14]
3 years ago
9

A 171 g sample of tetrafluoromethane (CF4) contains 90 g of carbon. What is the mass percent of fluorine in the compound?

Chemistry
2 answers:
inn [45]3 years ago
8 0
<span>To find the mass percent of fluorine in the compound, you must first determine the mass in g of fluorine in the compound. We do this by subtracting the mass of carbon from the total mass of the sample. From this we get 171 - 90 = 81g of fluorine in CF4 sample. Now to get the mass percent, we divide the fluorine mass by the sample mass to get the percent mass. 81/171 = .4737 which multiplied by 100 to get percentage give 47.37%.</span>
rodikova [14]3 years ago
8 0
<span>Mass of fluorine:171 g (compound ) - 90 ( carbon )  =>  81 g of

fluorinepercent of fluorine in the compound:

( 81 g F ) / 171 ( compound ) x  100 %

= 0,4737 x 100 = 47,37%

hope this helps!</span>
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Answer:

We need 12.26 grams H2SO4

Explanation:

Step 1: Data given

Volume of a H2SO4 solution = 500 mL = 0.500 L

Concentration of the H2SO4 solution = 0.250 M

Molar mass of H2SO4 = 98.08 g/mol

Step 2: Calculate moles H2SO4

Moles H2SO4 = concentration * volume

Moles H2SO4 = 0.250 M * 0.500 L

Moles H2SO4 = 0.125 moles

Step 3: Calculate mass of H2SO4

Mass of H2SO4 = moles * molar mass

Mass of H2SO4 = 0.125 moles * 98.08 g/mol

Mass of H2SO4 = 12.26 grams

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\color{pink} \rule{500pt}{100000000pt}

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