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3 years ago

A 171 g sample of tetrafluoromethane (CF4) contains 90 g of carbon. What is the mass percent of fluorine in the compound?

2 answers:

8 0

<span>To find the mass percent of fluorine in the compound, you must first determine the mass in g of fluorine in the compound. We do this by subtracting the mass of carbon from the total mass of the sample. From this we get 171 - 90 = 81g of fluorine in CF4 sample. Now to get the mass percent, we divide the fluorine mass by the sample mass to get the percent mass. 81/171 = .4737 which multiplied by 100 to get percentage give 47.37%.</span>

rodikova [14]3 years ago

8 0

<span>Mass of fluorine:171 g (compound ) - 90 ( carbon ) => 81 g of

fluorinepercent of fluorine in the compound:

( 81 g F ) / 171 ( compound ) x 100 %

= 0,4737 x 100 = 47,37%

hope this helps!</span>

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Molar mass NaHCO₃ = 23 + 1 + 12 + 16 x 3 = 84 g/mol

1 mole ---------- 84 g
? mole ---------- 110 g

moles NaHCO₃ = 110 . 1 / 84

moles NaHCO₃ = 110 / 84

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Explanation:

From the question we are told that:

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