To calculate this, we need to do the following:
92 * 115 = 10580 (we first multiply the percentage with our number)
10580 / 100 = 105.8 (and divide what we get by 100 to get the final answer)
And this is also already the answer: 105.8
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Least to greatest: 2/5, 3/5, 7/10, 3/4
23
Step-by-step explanation:



RATE BRAINLIEST
Answer:
Runner B
Step-by-step explanation:
speed = distance ÷ time
Runner A: 1 ÷ 8 = 0.125m/ms
Runner B: 2 ÷ 10 = 0.2m/ms
Runner C: 3 ÷ 20 = 0.15m/ms
Runner D: 5 ÷ 30 = 0.17m/ms
Runner B has the highest speed so he is the fastest runner.