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BabaBlast [244]

3 years ago

15

How do u combine like terms

2 answers:

velikii [3]3 years ago

6 0

If the equation is let's say 3x+ 7 +4x to combine like terms, you would take 3x and 4x since they both have x. You wouldn't take the 7 since it doesn't have and x like the other numbers. 3x +4x = 7x so your new equation would be 7x + 7.

emmasim [6.3K]3 years ago

5 0

Answer:

If the equation is let's say 3x+ 7 +4x to combine like terms, you would take 3x and 4x since they both have x. You wouldn't take the 7 since it doesn't have and x like the other numbers. 3x +4x = 7x so your new equation would be 7x + 7.

Read more on Brainly.com - brainly.com/question/10824149#readmore

Step-by-step explanation:

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Bubble map vocabulary<br><br> decimal

alisha [4.7K]

Decimal is the dot used after the ones to show parts of one you normally see it in money. 1.50. The . between 1 and 50 is the decimal. Whats in front of the decimal is ones, tens, hundreds, etc and after the decimal is tenths, hundredths, etc.

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6 0

3 years ago

A 1.8-ounce jar cinnamon costs $4.05. What is the cost per ounce?

Paha777 [63]

$4.05/1.8 oz= $2.25 per oz

Final answer: $2.25 per oz

6 0

3 years ago

Read 2 more answers

- A number r added to 3.7 is less than 1.2.

SIZIF [17.4K]

Answer:

3.7 + r < 1.2

Step-by-step explanation:

a number r added to 3.7 is 3.7 + r

New expression 3.7 + r should be less than 1.2 --->

3.7 + r < 1.2

7 0

4 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

or

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

or

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

4 years ago

Read 2 more answers

1) Mr. R and his wife looked to see how much money they had on them when they were out. Mr. Ratliff had $58.79 in his wallet. If

Maslowich

The equation would be 198.24 = x + 58.79

7 0

3 years ago