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Paha777 [63]
3 years ago
7

Simplify: (x - 2)(4x2 + 2x - 3) =

Mathematics
2 answers:
Archy [21]3 years ago
6 0

You have to multiply 4 x 2 first which gets you 8 -3 = 5 +2x

x - 2 + 5 +2x

I don't know for sure

SashulF [63]3 years ago
6 0
Polynomials YEEEEET
Okie dokie
I do it this way but you probs have another way.
(X-2)(4*2+2x-3)
(X-2)(8 + 2x - 3)
(X-2)(2x + 8-3)
(X-2)(2x + 5)
5(x-2) + 2x(x-2)
5x-10 + 2x^2 - 4x
2x^2 + x - 10. Remember to put your numbers in order when working out.
Okey chow byeeeeeee
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The ratio of athletes to non-athletes at bayside high school is 2 to 6. If there are 1200 non-athletes at school, how many athle
N76 [4]

Answer:

400

Step-by-step explanation:

4 0
3 years ago
Require full steps working for this question
Ray Of Light [21]

I let the computer do the graphing.  

f(x) = x(x + 3)²(1 - x) / 3

We see obvious zeros at x=0, x=-3 and x=1.

f(x) = x(x + 3)²(1 - x) / 3

f(x) = x(x^2 + 6x + 9)(1 - x)/3

f(x) = x(x^2 + 6x + 9 - x^3 - 6x^2 - 9x)/3

f(x) = x(- x^3 - 5x^2 -3x +9)/3

f(x) = (-x^4 - 5x^3 -3x^2 +9x)/3

f'(x) = (-4x^3 - 15x^2 -6x + 9)/3

We know there's f'(-3)=0 so x+3 must be a factor here,

f'(x) = (x + 3) (-4x^2 - 3x + 3)

We get stationary points when x = -3 or

x = (-1/8)( 3 ± √(9 - 4(-4)(3))) =  (-3 ± √57)/8  about -1.3 and 0.6 which are a local minimum and maximum respectively.

f''(x) = (-12x^2 - 30x -6)/3 = -4x^2 - 10x - 2

f''(-3) = -4(9)+ 30 - 2 = -8

Concave Down, Negative.   (-3,0) is a local maximum.

f''((-3 - √57)/8) = -4(-1.3)^2 - 10(-1.3) - 2 = 4.24

Concave up, positive, a CUP

(-3 - √57)/8, f((-3 - √57)/8) ) is a minimum.

f''((-3 + √57)/8) = -4(.6)^2 - 10(.6) - 2 = -9.44

CDN, ( ((-3 + √57)/8), f((-3 + √57)/8) ) is a maximum.

I didn't evaluate f((-3 ±√57)/8) which are around -3 and 1 but I leave that calculation to you.

6 0
3 years ago
Given that PS is the perpendicular bisector of QR, PQ=3.5m+18, and PR=6m+3, identify PQ.
kolbaska11 [484]

Answer:

PQ=39\ units

Step-by-step explanation:

we know that

QS=RS ----> equation A

Applying Pythagoras Theorem

PQ^2=SP^2+QS^2 -----> equation B

PR^2=SP^2+RS^2-----> equation C

substitute equation A in equation C

PR^2=SP^2+QS^2

we have that

PR^2=PQ^2

so

PR=PQ

substitute the given values

6m+3=3.5m+18

Solve for m

6m-3.5m=18-3

2.5m=15

m=6

Find the value of PQ

PQ=3.5m+18

substitute the value of m

PQ=3.5(6)+18

PQ=39\ units

8 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Chuge%20%5Cpink%7Bwhat%20%5C%3A%20is%20%5C%3A%20cranial%7D%20%5C%5C%20%5Chuge%20%5Cpink%7
worty [1.4K]

\huge\mathcal{\fcolorbox{aqua}{pink}{\blue{✿Answer ❖}}}

“Nerves that extend throughout the body on both sides emerging directly from brain and brain stem are called cranial nerves.”

6 0
3 years ago
What is the missing number? x-3=72?<br> Need help
AlladinOne [14]
Add 3 to 72... so 3 plus 72 is 75

X=75
8 0
3 years ago
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