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2 years ago

(3x)^2-2x^2 when x=-2

Mathematics

1 answer:

Leto [7]2 years ago

3 0

Hey there!

(3x)^2 - 2x^2

= (3(-2))^2 - 2(-2)^2

= -6^2 - 2(4)

= 36 - 8

= 28

Therefore, your answer is: 28

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Write the 2-digit number that matches the clues. My number has a tens digit that is 8 more than the ones digit. Zero is not one

laila [671]

Firstly attention should pe paid to the exact words given in the problem and then only the answer can be easily deduced.
It is a 2 digit number and that is said in the problem
Now For the tens digit it has been said that it is 8 more than the ones digit. The ones digit cannot be zero and that is already mentioned in the problem.
So if we take the ones digit to be 1, then the tens digit will be= 8 +1
= 9
Now if we take the ones digit to be 2, then the tens digit will be = 2 + 8
= 10
So it cannot be 2 as the tens digit takes the number to a 3 digit number and it is not possible.
So the answer to this problem is 91.

5 0

3 years ago

In the rectangle below, E1=2x -2, FH=3x+6, and m 4IHG =35°.Find Gl and m LIEH

Tpy6a [65]

Recall that the diagonals of a rectangle bisect each other and are congruent, therefore:

$\begin{gathered} FH=2EI, \\ GI=EI. \end{gathered}$

Substituting the given expression for each segment in the first equation, we get:

$3x+6=2(2x-2).$

Solving the above equation for x, we get:

$\begin{gathered} 3x+6=4x-4, \\ 3x+6+4=4x, \\ 3x+10=4x, \\ 4x-3x=10, \\ x=10. \end{gathered}$

Substituting x=10 in the equation for segment EI, we get:

$EI=2*10-2=20-2=18.$

Therefore:

$GI=18.$

Now, to determine the measure of angle IEH, we notice that:

$\Delta HFG\cong\Delta GEH,$

therefore,

$\measuredangle GHF\cong\measuredangle HGE.$

Using the facts that the triangles are right triangles and that the interior angles of a triangle add up to 180° we get:

$m\measuredangle IEH=90^{\circ}-35^{\circ}=55^{\circ}.$

<h2>Answer: </h2> $\begin{gathered} m\operatorname{\measuredangle}IEH=55^{\operatorname{\circ}}, \\ GI=18. \\ \end{gathered}$

4 0

1 year ago

Simplify completely 10x6y3+20x3y2/5x3y

Kryger [21]

Answer:

$\large\boxed{\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=2x^3y^2+4y}$

Step-by-step explanation:

$\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=\dfrac{(5x^3y)(2x^3y^2)+(5x^3y)(4y)}{5x^3y}\\\\=\dfrac{5x^3y(2x^3y^2+4y)}{5x^3y}\qquad\text{cancel}\ 5x^3y\\\\=2x^3y^2+4y$