All categories

3 years ago

Find the area of each composite figure. Use 3.14 for π. Round to the nearest tenth if necessary. Whats the correct label?

Mathematics

1 answer:

Leto [7]3 years ago

5 0

Answer:

i dont think this is wright but i got 48

Step-by-step explanation:

You might be interested in

An inequality represents an infinite amount of numbers smaller than 8. Which inequality represents the situation?

-Dominant- [34]

X < 8

what this question is saying is that a number, x, can be anything, as long as it is smaller than 8.

x < 8 represents that this sentence. X could be 7, it could be -1, it could be anything smaller than 8, but it could not be 8 or anything greater than 8.

8 0

3 years ago

Read 2 more answers

Can someone help solve 1 + 2x = 7?

Yanka [14]

Answer:

Step-by-step explanation:

1+2x=7

7-1=6

2x=6

6/2=3

x=3

5 0

3 years ago

Read 2 more answers

In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD

dmitriy555 [2]

Answer:

The area of parallelogram ABCD is $78.42 \mathrm{in}^{2}$

Explanation:

Given:

AD = 12 in

$m \angle C=46^{\circ}$

$m \angle D B A=72^{\circ}$

To Find:

The area of parallelogram ABCD=?

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.

The area of the parallelogram can be calculated by $a b * \sin (a n g l e)$

Substituting the value of a=12 we have

$\text { Area of parallelogram }=12 * \text { bsin } 46$

<u>To find the value of b, </u>

We know that area of a triangle can be expressed as,

$\text { Area of triangle }=(A b / 2) \sin (\text {angle})$

So,

$(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72$

Cancelling BD and 2 on both sides we get,

$12 * \sin 46=A B * \sin 72$

$A B=12 * \frac{\sin 46}{\sin 72}$

Therefore,

$b=\frac{12 \sin 46}{\sin 72}$

Substituting the value of b,

$=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46$

=78.42

So the area of the parallelogram is $78.42 \mathrm{in}^{2}$

6 0

3 years ago

Read 2 more answers

A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe

Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

Length of the Larger Rectangle =80+2w
Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

$1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.$

6 0

3 years ago

What unit of time or volume is 1 equals 2?

Ugo [173]

What exactly are you asking?

5 0

3 years ago