2 years ago

How would I put this into an equation form?

Mathematics

1 answer:

Hitman42 [59]2 years ago

6 0

Answer:

how would you put what? there isn't an image or problem

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If a < 0 then the graph opens_____

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Answer:

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Step-by-step explanation:

Assuming this is for a parabola

a>0 the graph opens up

a < 0 the graph opens down

( negative is a frown)

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the equation of line cd is y = 3x − 3. write an equation of a line perpendicular to line cd in slope-intercept form that contain

liberstina [14]

Answer:

The required equation is $y=-\frac{1}{3}x+2$ .

Step-by-step explanation:

The equation of line cd is

$y=3x-3$

Slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

Slope of line cd is 3.

The product of slopes of two perpendicular lines is -1.

$m_1\times m_2=-1$

$3\times m_2=-1$

$m_2=-\frac{1}{3}$

Therefore slope of perpendicular line is $-\frac{1}{3}$ .

Point slope form of a line is

$y-y_1=m(x-x_1)$

Slope of perpendicular line is $-\frac{1}{3}$ and line passing through the point (3,1).

$y-1=-\frac{1}{3}(x-3)$

$y=-\frac{1}{3}x+1+1$

$y=-\frac{1}{3}x+2$

Therefore the required equation is $y=-\frac{1}{3}x+2$ .

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Step-by-step explanation:

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Step-by-step explanation:

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