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masya89 [10]
3 years ago
11

2. Evaluate each function at the specific value

Mathematics
1 answer:
Oliga [24]3 years ago
8 0
F(6) says “take f(x) = -4x + 11 and put 6 in for every x-value and then clean it up.”

f(6) = -4(6) + 11
     
      = -24 + 11

      = -13


f(x) = -1 says “set your function equal to -1 and solve for x”

    f(x) = -1

-4x+11 = -1

-4x = -12

        x = 3

So f(3) = -1.
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Please Hurry :) Alexis is writing a book about stand-up comedians and how to survive the comedy circuit. Because she took her sw
jek_recluse [69]
I don’t see what your asking, theres no question. This is a statement.
5 0
3 years ago
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

8 0
2 years ago
Write 4/28 in simplest form
77julia77 [94]
Simplists form is 1/7


7 0
3 years ago
Read 2 more answers
The product of two consecutive even positive integers is one hundred twenty. fined the integers
AfilCa [17]
Product is multiplication:

x * (x+2) = 201

x^2 +2x = 120

x^2 + 2x -120 = 0

(x+12) (x-10) = 0

x = -12 and x = 10

-12 x -1 = 12

 the 2 numbers are 10 and 12

3 0
3 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
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