2 years ago

Solve the polynomial (ab ^ 2 +13b-4a) + (3ab ^ 2 + a)

Mathematics

1 answer:

scoundrel [369]2 years ago

8 0

Answer: 4ab2 - 3a + 13b

Step-by-step explanation: (a•(b2))+13b)-4a)+(3ab2+a)

Factoring 4ab2 - 3a + 13b

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Simplify (2z^5)(12z^3)/4z^4

Sphinxa [80]

Answer:

$6z^{4}$

Step-by-step explanation:

Given in the question an expression,

$\frac{ (2z^5)(12z^3)}{4z^4}$

Step 1

Apply exponential "product rule"

$x^{m}x^{n}=x^{m+n}$

$\frac{ 12(2)z^5)(z^3)}{4z^4}$

$\frac{ (24)z^5)(z^3)}{4z^4}$

$\frac{ 24(z^{(5+3)})}{4z^4}$

$\frac{ 24(z^{8})}{4z^4}$

Step 2

Apply exponential " divide rule"

$\frac{x^{m}}{x^{n}}=x^{m-n}$

$\frac{24/4(z^{8})}{z^4}$

$\frac{6(z^{8})}{z^4}$

$\frac{6(z^{8-4})}{1}$

$6z^{4}$

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2 years ago

Zene deposited $50 in a savings account earning 5% interest, compounded annually. To thenearest cent, how much will he have in 3

JulsSmile [24]

Answer:

$\$57.88$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=3\ years\\ P=\$50\\ r=5\%=5/100=0.05\\n=1$

substitute in the formula above

$A=50(1+\frac{0.05}{1})^{1*3}$

$A=50(1.05)^{3}$

$A=\$57.88$

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3 years ago

Simplify the following expression. −3√84x3

prisoha [69]

Answer:

-18root7

Step-by-step explanation:

-3root 84*3

-3root4*7*3*3

-3(2*3)root7

-18root7

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3 years ago

Given that the point (8, 3) lies on the graph of g(x) = log2x, which point lies on the graph of f(x) = log2(x + 3) + 2?

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The next one is x>-3

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2 years ago

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What is the square root of 10,000

Setler [38]

100 and -100 are the two solutions for the square root of 10,000

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