Finding the square<span> root of a </span>number<span> is the inverse operation of squaring that </span>number<span>. Remember, the </span>square<span> of a </span>number<span> is that </span>number<span> times itself. The perfect squares are the squares of the whole </span>numbers<span>. The </span>square<span> root of a </span>number<span>, n, written below is the </span>number<span> that gives n when multiplied by itself.
</span>
First we have to rewrite this function.Instead of :^3 sqrt (...) we can write : (...)^(1/3).
f ( x ) = ( 27 x - 81 ) ^(1/3) - 5 = ( 27 * ( x - 3 ) ) ^(1/3) - 5 = = 3 * ( x - 3 )^(1/3) - 5 And this makes it easy to graph a translation.The parent function is y = x^(1/3). The zero of this function is ( 0, 0 ).
Then it will be stretched vertically by a factor of 2 and translated: 3 units right and 5 units down.
Answer:
y = -x/6 + 2
Step-by-step explanation:
Answer:
12/13
Step-by-step explanation:
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Since the reference angle is P, hence;
MN is the opposite = 5
MO is the hypotenuse = 13 (longest side)
NO is the adjacent = 12
Cos O = adj/hyp
Substitute the given values
Cos O = 12/13
Hence the value of Cos O is 12/13
