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Sunny_sXe [5.5K]

2 years ago

8

Solve the polynomial (ab ^ 2 +13b-4a) + (3ab ^ 2 + a)

1 answer:

scoundrel [369]2 years ago

8 0

Answer: 4ab2 - 3a + 13b

Step-by-step explanation: (a•(b2))+13b)-4a)+(3ab2+a)

Factoring 4ab2 - 3a + 13b

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Pick any Martin Luther king speech 2-4 minutes and pick a inspirational reason why you picked that speech

love history [14]

Answer:

chrjmgovu huh tictok conductivity sleep

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3 years ago

The simple interest on a loan of $6000 for 3 years was $900. What was the rate of interest per annum

Thepotemich [5.8K]

Answer:

5%

Step-by-step explanation:

900/3=300

300/6000=0.05

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7 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

3X-4 over 14 equals 9 over 10 solve for x

Maru [420]

Answer:

3x-4/14=9/10

You change the subtraction to addition

3x+4/14=9/10

Then you change the fractions to decimals

Step-by-step explanation:

8 0

3 years ago

Thomas bought 7 dozen roses for the wedding. The roses were divided equally into 6 equal vases. How many roses are in each vase?

dlinn [17]

There are 14 roses in each vase.

5 0

3 years ago

Read 2 more answers