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3 years ago

When solving a system of two equations via substitution, there will always be only one answer.

1 answer:

6 0

No false.
Remember the solution(s) to a system of equations is where the graphs all intersect if at all.
For the case of say a system of 2 lines, you can see the different possible outcomes..
-- If the two lines intersect at some point (x,y), that is one unique solution
-- If the two lines are parallel to each other, you see there are no intersection points and therefore this system of two parallel lines has no solutuion.
-- If the two lines overlap, really the same line written as a multiple of the other line, then you see they intersect at all points along the line, here there are infinite solutions.

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Alicia drew a map of Texas. In the scale Alicia used for the map, 12 inch represents 20 miles. What is the distance between two

LekaFEV [45]

Answer:

216 inches

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help Help!!!!!!!!!!!!!!!

BabaBlast [244]

Answer:

$\frac{7}{10} y$

Step-by-step explanation:

To add fractions with the same denominator, simply add the numerators:

$\frac{a}{b} + \frac{c}{b} = \frac{a+c}{b}$

So:

$\frac{3}{10} y+\frac{4}{10} y=\frac{7}{10} y$

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3 years ago

Algebraic expressions and translations Solve -3+5×=8

vovangra [49]

Answer:

x = 11/5

Step-by-step explanation:

-3 + 5x = 8

5x = 8 + 3

5x = 11

x = 11/5

Mark me brainliest

8 0

4 years ago

Alexa used her compass to evenly divide the circumference of the circle below.

jok3333 [9.3K]

Answer:

triangle
square
hexagon
dodecagon

Step-by-step explanation:

The 12 points marked can be divided into this many equal-size groups:

3, 4, 6, 12

so the figures that can be constructed are ...

triangle . . . . connects every 4th mark
square . . . . . connects every 3rd mark
hexagon . . . .connects every other mark
dodecagon . . connects every mark

_____

12 is also divisible by 1 and 2, but the minimum number of vertices in a regular polygon is 3.

3 0

3 years ago

Plz help urgent !!!! will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...

$\begin{bmatrix}1&3\\ 2&4\end{bmatrix}$ ... which is our solution.

7 0

3 years ago