What is a possible value for the missing term of the geometric sequences?

2 answers:

8 0

A(n)=ar^(n-1) and we can find the rate upon using the ratio of two points...

50/1250=1250r^2/1250r^0

1/25=r^2

r=1/5 so

a(n)=1250(1/5)^1=250

...

You could have also found the geometric mean which is actually quite efficient too...

The geometric mean is equal to the product of a set of elements raised to the 1/n the power where n is the number of multiplicands...in this case:

gm=(1250*50)^(1/2)=250

babymother [125]2 years ago

6 0

The answer is:

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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al

Furkat [3]

Answer: $\frac{\sqrt[4]{10xy^3}}{2y}$

where y is positive.

The 2y in the denominator is not inside the fourth root

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Work Shown:

$\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\$

The idea is to get something of the form $a^4$ in the denominator. In this case, $a = 2y$

To be able to reach the $16y^4$ , your teacher gave the hint to multiply top and bottom by $2y^3$

For more examples, search out "rationalizing the denominator".

Keep in mind that $\sqrt[4]{(2y)^4} = 2y$ only works if y isn't negative.

If y could be negative, then we'd have to say $\sqrt[4]{(2y)^4} = |2y|$ . The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0

2 years ago

A high school has 2,000 students.

Rama09 [41]

Answer:

18 students

Step-by-step explanation:

I TOOK THE TEST Pls mark brainliest...

8 0

2 years ago

Answer choices are 14 24 28 48

MrRa [10]

Answer: 24 square units

Step-by-step explanation:

It appears the shaded area of the rectangle is half of the rectangle's area. This means if we find the area of the rectangle and divide it by 2 we will know the area of the shaded portion.

The formula for the area of a rectangle is $lw=A$