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sdas [7]
3 years ago
6

You study for a test and you believe you'll get an A on the test. This is an example of: A) conclusion B) prediction C) inferenc

e D) hypothesis
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

B

Step-by-step explanation:

You might be interested in
How to wirte a linear equation from a graph
astra-53 [7]
Hey there!
I'll assume we're using the slope-intercept form equation:
y = mx + b
m = slope
b = y-intercept
First, we keep the y, because it's value depends on the x value given.
Next, we find the slope. Slope is defined as rise/run, so we take two points on the graph, find how much taller one is from another, and how far right/left they are, put those values over each other, and we have out slope (m).
Finally, we need to determine the y-intercept, and that's as simple as seeing where the line crosses the y axis and writing down that value.
Hope this helps!
8 0
3 years ago
Simplify the expression using the distributive property. –4(–3x + 11) 1. Distribute the –4 through the parentheses: -4(–3x) + (-
gayaneshka [121]

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5 0
3 years ago
11b-7-3n+8-5b+9n what is the answer
Sergio [31]

Answer:

6 n + 6 b + 1

Step-by-step explanation:

Simplify the following:

11 b - 7 - 3 n + 8 - 5 b + 9 n

Grouping like terms, 11 b - 7 - 3 n + 8 - 5 b + 9 n = (9 n - 3 n) + (11 b - 5 b) + (8 - 7):

(9 n - 3 n) + (11 b - 5 b) + (8 - 7)

9 n - 3 n = 6 n:

6 n + (11 b - 5 b) + (8 - 7)

11 b - 5 b = 6 b:

6 n + 6 b + (8 - 7)

8 - 7 = 1:

Answer: 6 n + 6 b + 1

4 0
3 years ago
Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join
zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx  = 1

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y)  and replacing a and b with their respective values, we have

\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx  = 1

Since c is a constant, we can bring it out of the integral sign; to give us

c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx  = 1

Open the bracket

c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

Integrate with respect to y

c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

Substitute 0 and 3 for y

c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

c\int\limits^3_0 {(\frac{x* 9}{2}  +\frac{x * 27}{3} ) - (0  +0) \, dx = 1

c\int\limits^3_0 {(\frac{9x}{2}  +\frac{27x}{3} )  \, dx = 1

Add fraction

c\int\limits^3_0 {(\frac{27x + 54x}{6})  \, dx = 1

c\int\limits^3_0 {\frac{81x}{6}  \, dx = 1

Rewrite;

c\int\limits^3_0 (81x * \frac{1}{6})  \, dx = 1

The \frac{1}{6} is a constant, so it can be removed from the integral sign to give

c * \frac{1}{6}\int\limits^3_0 (81x )  \, dx = 1

\frac{c}{6}\int\limits^3_0 (81x )  \, dx = 1

Integrate with respect to x

\frac{c}{6} *  \frac{81x^{2}}{2}   (0,3)  = 1

Substitute 0 and 3 for x

\frac{c}{6} *  \frac{81 * 3^{2} - 81 * 0^{2}}{2}    = 1

\frac{c}{6} *  \frac{81 * 9 - 0}{2}    = 1

\frac{c}{6} *  \frac{729}{2}    = 1

\frac{729c}{12}    = 1

Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

8 0
3 years ago
Sofia is making a copy of a ticket from the school play to put in her memory album. the original ticket is 7 inches long and 5 i
kotykmax [81]

Answer:

The scale of the copy of the ticket is \frac{2}{7}

Step-by-step explanation:

we know that

To find the scale divide the long of the copy of a ticket by the long of the original of a ticket

so

\frac{2}{7}

7 0
3 years ago
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