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Montano1993 [528]
4 years ago
15

PLEASE HELP

Chemistry
2 answers:
Serhud [2]4 years ago
6 0

Answer:

The answer to your question is: number 2 is correct.

Explanation:

Formula

                     F   =  m  x  a

                     a = \frac{F}{m}

The formula shows that acceleration and mass and inversely proportional, then if the mass increases 3 times, then the acceleration must diminishes 3 times.

1. The object will accelerate the same amount as before because the mass does not affect the object’s acceleration. This option is incorrect, the acceleration must diminish.

2. The object will accelerate 1/3 as much because if you apply the same net force but increase the mass, the acceleration will decrease.  This option is correct, is what i describe above.

3. The object will not accelerate because now it is too heavy. this option is wrong, because the object will accelerate.

4. The object will accelerate 3 times as much because if you apply the same net force and increase the mass, the acceleration will increase. This option s incorrect, the acceleration will diminish not increase.

Feliz [49]4 years ago
6 0

Answer:

2.  The object will accelerate 1/3 as much because if you apply the same net force but increase the mass, the acceleration will decrease.

Explanation:

This is an example of Newton's Second Law of motion.

Force = mass * acceleration (a).

So if the  mass is m and the force is 2:

2 = m * a  So a = 2/m

If the mass is increased  to 3m then

2 = 3m * a2   where a2 is the new acceleration, so  

a2 = 2/3m.

Comparing the 2 accelerations:

= 2/3m / 2/m

= 2/3m * m /2

= 2/6

= 1/3 of the previous acceleration.

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8 0
4 years ago
For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow
lora16 [44]

Answer:

Rate constant of the reaction is 3.3\times 10^{-3} M^{-2} s^{-1}.

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

R=k[A]^a[B]^b[C]^c

Rate(R) of the reaction in trail 1 ,when :

[A]=0.30 M,[B]=0.30 M,[C]=0.30 M

R=9.0\times 10^{-5} M/s

9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c...[1]

Rate(R) of the reaction in trail 2 ,when :

[A]=0.30 M,[B]=0.30 M,[C]=0.90 M

R=2.7\times 10^{-4} M/s

2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c...[2]

Rate(R) of the reaction in trail 3 ,when :

[A]=0.60 M,[B]=0.30 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c...[3]

Rate(R) of the reaction in trail 4 ,when :

[A]=0.60 M,[B]=0.60 M,[C]=0.30 M

R=3.6\times 10^{-4} M/s

3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

R=k[A]^2[B]^0[C]^1

Rate constant of the reaction = k

9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1

k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}

k=3.3\times 10^{-3} M^{-2} s^{-1}

7 0
3 years ago
What is the relationship between the word pairs in this analogy? dull: boring as amusing: entertaining O A. Synonyms O B. Antony
leva [86]

Answer:

A: Synonyms

Explanation:

Synonyms are two words that have same meaning but are different words (tell me if this works!)

8 0
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