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abruzzese [7]
3 years ago
6

The distance between (-2,2) (-8,-6)

Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0
So you have to use a formula y2-y1/x2-x1.
Which looks like -6-2/-8-2 = 4/5
So 4/5 is the answer!
You might be interested in
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
What is the value of x in the equation 2x - 3 = 9- 4x? o 6 o 3 O 1 02​
riadik2000 [5.3K]

Answer:

2? The last one

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Need Help...
Rudik [331]
<span>|7x-7|+3 = 4x+1  ⇒⇒⇒ add (-3) to both sides
</span>
<span>∴ |7x-7| = 4x - 2
</span>
According to the absolute rule
∴ 7x - 7 = 4x - 2    OR    -(7x - 7) = 4x - 2                                 
    7x - 4x = 7 - 2      l     7x - 7 = -4x + 2                              
   3x = 5                   l     7x + 4x = 2 + 7                                         
  x = 5/3                   l     11 x = 9  ⇒⇒⇒  x = 9/11

∴ x = 5/3  and  9/11


So, the correct answer is option <span>B. 5/3 and 9/11</span>


5 0
3 years ago
Find the equations of the tangent lines to x2+y2=1 at x=0, x=1 and x=35.
Ivanshal [37]
Assuming the equation is x^2 + y^2 = 1, then that's a circle, with radius 1, centered on the origin [0,0].

So there are two tangents at x = 0. They are y = 1, and y = -1 (horizontal lines).

There is one tangent at x = 1. It is x = 1 (a vertical line).

There is no tangent at x = 35, because the original equation has no solution at x = 35.
4 0
3 years ago
What is the midpoint M of that line segment?
topjm [15]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ T(\stackrel{x_1}{6}~,~\stackrel{y_1}{3})\qquad U(\stackrel{x_2}{6}~,~\stackrel{y_2}{9}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+6}{2}~~,~~\cfrac{9+3}{2} \right)\implies \left( \cfrac{12}{2}~~,~~\cfrac{12}{2} \right)\implies \stackrel{M}{(6,6)}

3 0
3 years ago
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