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Ymorist [56]
3 years ago
14

HIII ANOTHER ONE last one was blurry. ty guys!!

Mathematics
1 answer:
nikklg [1K]3 years ago
5 0

Answer:

The second one

Step-by-step explanation:

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Plz help I will give brainliest
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#8. M = -8/9

#9. M = 3/5

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G(x)=-3x+2 and g(x)=-1, find x
Zinaida [17]

Answer:

x=1

Step-by-step explanation:

7 0
3 years ago
Imagine a player getting ready for a tournament. He has 4 games to play during the day: 9:00 a.M., 11:00 a.M., 1:00 p.M., and 3:
Feliz [49]

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by game 3(at 1:00 p.m.)

temperature increases to 5 degrees at 1:00 p.m

8 0
3 years ago
write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)
gladu [14]
Find midpoint of segment.
(-1,1), (7,-5)
x= \frac{-1+7}{2}=3,y= \frac{1+(-5)}{2}=-2

Find slope of line which passes through (-1,1) and (7,-5).
m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}

The slope of perpendicular line is negative reciprocal value of m.
m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}

Write quation of line which slope is \frac{4}{3} and passes throug the point (3,-2).
m=\frac{4}{3},x_1=3,y_1=-2
\\y-y_1=m(x-x_1)
\\
\\y-(-2)=\frac{4}{3}(x-3)
\\
\\y+2=\frac{4}{3}x-\frac{8}{3}
\\
\\3y+6=4x-8
\\4x-3y-14=0

3 0
3 years ago
10
Novay_Z [31]

Answer:

The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the <u>line y = x</u> and a translation <u>10 units right and 4 units up</u>, equivalent to T₍₁₀, ₄₎

Step-by-step explanation:

For a reflection across the line y = -x, we have, (x, y) → (y, x)

Therefore, the point of the preimage A(-6, 2) before the reflection, becomes the point A''(2, -6) after the reflection across the line y = -x

The translation from the point A''(2, -6) to the point A'(12, -2) is T(10, 4)

Given that rotation and translation transformations are rigid transformations, the transformations that maps point A to A' will also map points B and C to points B' and C'

Therefore, a sequence of transformation maps ΔABC to ΔA'B'C'. The sequence of transformations that maps ΔABC to ΔA'B'C' is the reflection across the line y = x and a translation 10 units right and 4 units up, which is T₍₁₀, ₄₎

5 0
3 years ago
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