All categories

3 years ago

Help me quickkkk!! A = 1/2(a+b)h solve for b

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Answer:

2A/h - a = b

Step-by-step explanation:

Using A= 1/2(a+b)h

Divide both side by h

⇒A/h = 1/2(a + b)

Mutiply both sides by 2

⇒2A/h = a + b

Take the 2 over to the other side

2A/h - a = b

Keep in mind, that the (a) is not on the bottom, rather on its own

You might be interested in

What shape is in the interior of these four lines? Classify it.

Airida [17]

Answer:

parallelogram

Step-by-step explanation:

5 0

2 years ago

How do i do this problem (7 3/8) - (4 5/8)

Sergio [31]

Answer:

Step-by-step explanation:

52 52 52 52 52 52 52 52

4 0

3 years ago

If a+b+c =0 show that a³+b³+c³= 3abc

slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0

3 years ago

Pls help your going to help my dead soulll

deff fn [24]

0.875 seconds
Can you give me brainliest please

4 0

3 years ago

Fgh is first translated using the rule x,y >x+3,y-1this is followed by a 90 degrees counter clockwise rotation centered at th

maw [93]

Answer:

Rule:

$h = (1 - y,x + 3)$

Step-by-step explanation:

I will answer generally, since the coordinates of f, g and h are not given

Given

Point: x, y

Translation Rule

1 : x + 3, y - 1

2: 90 degree counterclockwise

Required

Determine the new coordinates

At the first translation of (x,y) by x + 3, y - 1

The new point is: $(x + 3, y - 1)$

At the second translation (90 degrees counterclockwise)

When a point (x,y) is translated using this rule, it becomes (-y,x)

So, the new point is:

$h = (-(y - 1),x + 3)$

$h = (1 - y,x + 3)$

If the initial point of h is (2,3),

The new point is:

$h = (1 - 3, 2 + 3)$

$h = (- 2, 5)$

5 0

2 years ago