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Verizon [17]
3 years ago
6

PLS HELP VERY URGENT

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

well there is a formula for this type of problem...

but the given points are exactly 14 units apart...

dividing by (4+3)= 7, so the ration is 14/7 = 2

therefore we need the point that is 2*4=8 from one end

and 2*3 = 6 from the other end, so that their distance is 8+6=14

that must be (-7,-1)

Step-by-step explanation:

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For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative
trapecia [35]

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = -8(1)+0(3)+1(-3)\\= -11

Projection of U on V =\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }

Similarly projection of V on U

=\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }

4 0
3 years ago
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
3 years ago
F(x)=5x^5+ 24x^4+25x^3-86x^2-224x+48
Serjik [45]
I believe you graph this.. please let me know if wrong and I’ll help solve otherwise! The picture is the answer on how to graph

4 0
3 years ago
What is the x-intercept of the line that passes though the point (5, 3) with a slope of - 2/5?
lukranit [14]
Point/Slope Form of an equation!

(5,3)

slope of -2/5

x= 5
y = 3

y - y1 = m(x-x1)

y - 3 = -2/5(x-5)

y - 3 = -2/5x + 2

y = -2/5x + 5

x intercept of 5
4 0
3 years ago
Pls help Being timed
umka2103 [35]
(-6)-(+8)-(-12)
-6-8+12
-14+12
-2
3 0
3 years ago
Read 2 more answers
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