In this question it is given that the promoter first purchased 2 3/4 of ads at first. When one of the concerts got cancelled, then the promoter cancels 1 5/8 pages of ads. It is required to be found the number of pages the promoter is using finally.
Number of pages bought by the concert promoter initially = 2 3/4
= 11/4 pages
Number of pages cancelled by the promoter
after one concert got cancelled = 1 5/8
= 13/8 pages
Then the total number of pages finally used by the promoter = (11/4) - (13/8)
= (44 -13)/8
= 31/8
= 3 7/8 pages
So the total amount of space used for ads by the concert promoter is 3 7/8 pages.
If the test is a major grade ( 60% of final grade) then around 73-75 but if the grade is worth a daily grade (40% of final grade) 78-82
This is a simple addition/subtraction question question
4+3 = 7 km 12-7 = 4 therefore he still has 4 km to go
I’m not sure if you meant to put them in fraction form or not, but if you meant to put them as fractions (4 3/5) (6 1/5) then the answer would be
46.81
Answer:Option (B)
Step-by-step explanation:
