For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have the following equation:
![y = 3x-8](https://tex.z-dn.net/?f=y%20%3D%203x-8)
Thus, we have to:![m = 3\\b = -8](https://tex.z-dn.net/?f=m%20%3D%203%5C%5Cb%20%3D%20-8)
Therefore, the given equation is of the slope-intersection form.
Answer:
Option B
The answer is as follows
x = -3
y = 7
There are a few ways to do this but lets do it the following way.
<span>3x + y = -2
y = -x +4 <--- turn this to standard form
</span>
y = -x + 4
x + y = 4
3x + y = -2
x + y = 4 <---- Times this by -3 to cancel out
3x + y = -2
-3(x + y) = 4 * -3
3x + y = -2
-3x -3y = -12
+ y = -2
-3y = -12
-2y = - 14
-2y / -2 = - 14 / -2
y = 7
Now that we found y we can insert 7 into the y position in one of the equation. For instance
y = -x +4
7 = -x + 4
7 = -x + 4
-4 + 7 = -x
3 = -x
x = -3
Answer:
3 lines of symmetry
Step-by-step explanation:
Symmetry : Reflected images.
In the picture, there are 6 lines. We can connect 2 of the lines to make a line of symmetry. That will make 3 lines.
Answer:
Height of building is 76 feets
Step-by-step explanation:
The scenario is illustrated in the attached photo. The stretched rope is seen coming from the top of the building, passing through the top of the tree which is halfway the height of the building and touching the state which is on the ground.
The distance, x of the tree to the building on the ground is equal to the distance, x of the tree from the stake, hence,
Distance of the stake from the building is 2x
Height of the tree = 38 feets
Height of the building = y feets
The triangles formed are similar triangles. Therefore,
38/x = y/2x
Cross multiplying
2x × 38 = x × y
xy = 76x
y = 76x/x = 76 feets