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3 years ago

Select the two binomials that are factors of this trinomial.

Mathematics

1 answer:

Stella [2.4K]3 years ago

4 0

we are given

trinomial as

$x^2 -x -12$

now, we can factor it

$x^2 -x -12= x^2 -4x +3x -4*3$

$x^2 -x -12= x(x -4) +3(x -4)$

$x^2 -x -12= (x-4)(x+3)$

so, option-C and D ..............Answer

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Ostrovityanka [42]

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3 years ago

the first three steps of completing the square to solve the quadratic equation X2+4X-6=0 are shown below. what re the next 3 ste

Vilka [71]

Answer:

see the explanation

Step-by-step explanation:

The complete question is

The first three steps of completing the square to solve the quadratic equation x2 +4x -6= 0, are shown below.

Step 1: x2 +4x= 6

Step 2: x2 +4x+4=6+4

Step 3: (x +2)^2=10

What are the next 3 steps?

we have

step 4

Take square root both sides

$\sqrt{(x+2)^2} =\sqrt{10}$

step 5

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step 6

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2 years ago

What's the product: (12x+1)(3x-8)

jasenka [17]

Answer:

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Step-by-step explanation:

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3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

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$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

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$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

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2 years ago

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Answer:

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3 years ago