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Margaret [11]
2 years ago
14

Solve Spam: bdkenebekebevskzbbwj Wiennerjebbenejdxbddjjdkdkkcshjejd d

Mathematics
1 answer:
Svetach [21]2 years ago
4 0

Answer:439.2$

Step-by-step explanation:

So first there are 52 people who use the cleaning service right? therefore lets do 52 people  times the amount paid each month 12.20$ = 634.4$

16 members in the first week times 12.20 = 195.2$

so then subtract 634.4-195.2= your answer of 439.2 $ were collected the second week

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In 3/4 pound of spice mix, there are 5/6 cups of cinnamon.
earnstyle [38]

Answer:

9\div 10

Step-by-step explanation:

5\div 8

to get cinnamon qty  in the spice we do5\div 6\div 3\div 4

5 0
3 years ago
Suppose that Y has a gamma distribution with parameters α and β. a If a is any positive or negative value such that α + a > 0
Nookie1986 [14]

Answer:

2nd option

Step-by-step explanation:

makes most sense

3 0
3 years ago
Rewrite the equation y – 4x = –9 in slope-intercept form. simple explanation and proof
dusya [7]

Answer:

y=4x-9

Step-by-step explanation:

add 4x to both sides to isolate y

4 0
2 years ago
Read 2 more answers
Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [
Darya [45]

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

3 0
3 years ago
An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the
Sergio039 [100]

Answer:

The estimate is  P__{hat}} \pm E  = 0.37 \pm 0.0348

Step-by-step explanation:

From the question we are told that  

    The sample size is  n =  522

    The sample proportion of students  would like to talk about school is  \r p__{hat}} =  0.37

  Given that the confidence level is  90 % then the level of significance can be mathematically evaluated as

                  \alpha  =  100 - 90

                  \alpha  =  10\%

                  \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is  

               Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } =  1.645

Generally the margin of error can be mathematically represented as

               E =  Z_{\frac{\alpha }{2} } *  \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }

=>            E = 1.645 *  \sqrt{\frac{0.37 (1- 0.37  )}{522 } }

=>             E = 0.0348

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is  

                       P__{hat}} \pm  E

substituting values

                     0.37 \pm 0.0348

5 0
3 years ago
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