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andreyandreev [35.5K]
3 years ago
12

What is kinematics???explain!!! ​

Physics
2 answers:
steposvetlana [31]3 years ago
7 0

Answer:

the branch of physics that deals with study of motion of objects.....

Lol....xD

jek_recluse [69]3 years ago
3 0

Answer:

Kinematics is the study of motion, without any reference to the forces that cause the motion. It basically means studying how things are moving, not why they're moving. It includes concepts such as distance or displacement, speed or velocity, and acceleration, and it looks at how those values vary over time

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A 5kg goes from 4m/s to 20m/s determine the change in momentum
lukranit [14]

Answer:

i might know the answer to this, so can you help me with my question too?

Explanation:

5 0
3 years ago
Why are wheels and steam engine important in the history of transport​
STALIN [3.7K]

Explanation:

Because it's a power to turn the wheels of industry

5 0
3 years ago
A dripping water faucet steadily releases drops 1.0 s apart. As these drops fall, does the distance between them increase, decre
ololo11 [35]

Answer:

Distance between them increase

Explanation:

The position S of the water droplet can be determined  using equation of motion

S=ut+\frac{1}{2}  at^2

where u is the initial velocity which is zero here

t is time taken, a is acceleration due to gravity

the position of  first drop after time t is given by

S_{1}  =0 \times t+ \frac{1}{2} at^2=\frac{1}{2} at^2............(1)

the position of  next drop at same time is

S_{2}  =\frac{1}{2} a(t-1)^2 = \frac{1}{2} a(t^2+1-2t)............(2)

distance between them is S_{1} -S_{2}  is a(t-1)

from the above the difference will increase with the time

3 0
3 years ago
David is driving a steady 28.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady
rodikova [14]

Answer:

Explanation:

Let t represent the time for Tina to catch David.

Hence, considering the equation of linear motion S = ut + 1/2at^2..... 1

For David u = 28.0 m/s where 'a' is set to nought

S = ut

S = 28t.......2

For Tina consider equation 1

Where acceleration = 2.90m/s^2 and u is set at nought

S = 1/2×2.90 m/s×t^2.......3

Equate 2 and 3

28t = 1.45t^2

Divide through by t

28 = 1.45t

t = 28/1.45

t = 19.31seconds

Now put the value of t into equation 3

S = 1/2×2.90 m/s×t^2.......3

= 1.45×20×20

= 580m

Tina must have driven 580meters before passing David

Considering the equation of linear motion : V^2 = U^2+2as

Where u is set at nought

V^2 = 2as

V^2 = 2×2.9×580

V^2 = 3364

V = √3364

V = 58m/s

Her speed will be 58m/s

7 0
3 years ago
How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and
aev [14]

Answer:

h= 46.66 m

Explanation:

Given that

Initial speed of the car ,u = 110 km/h

We know that

1 km/h= 0.277 m/s

u= 30.55 m/s

lets height gain by car is h.

The final speed of the car will be zero at height h.

v²=u²- 2 g h

v= 0 m/s

0²=30.55²- 2 x 10 x h           ( g = 10 m/s²)

h= 46.66 m

4 0
4 years ago
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