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4 years ago

Choose all the answers that apply.

Physics

2 answers:

kozerog [31]4 years ago

8 0

Answer:

Skipping a cool-down can cause them.

They take rest to heal.

A broken bone is one type.

Tendonitis is one type.

Explanation:

Olenka [21]4 years ago

5 0

Answer:

<h3>Skipping a cool-down can cause them.</h3><h3>They take rest to heal.</h3><h3>A broken bone is one type.</h3><h3>Tendonitis is one type.</h3>

Explanation:

<em>Overuse injuries represent any type of muscle or bone injury caused by repetitive trauma as tendinitis or stress fractures.</em> <u>The most common overuse injuries are from muscle and bone overuse,</u> when the athlete don't rest properly, the excess of activity push muscles and bones out of the limit. Also, training errors conduct to these injuries.

Overuse injuries can be caused by skipping cool-down periods, or rest periods, that's what get the athlete in a overuse state. After these injuries occur, to rest is mandatory, it's the only way to heal, because muscles and bone need to stop to recover from the wide time use.

In addition, as we said before, tendinitis and stress fractures are the most common overuse injuries, due to the overuse of tendons and bones, at that point, they stress and become vulnerable.

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A friend of yours is loudly singing a single note at 412 Hz while racing toward you at 23.0 m/s on a day when the speed of sound

kobusy [5.1K]

Doppler Effect is required to solve the problem. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. The general formula of observed frequency, due to Doppler's effect is as follows,

$f_0 = (\frac{v+v_0}{v-v_s})f_s$

$f_0$ = Frequency observed by observer

v = Velocity of Sound

$v_0$ = Velocity of observer

$v_s$ = Velocity of source

$f_s$ = Frequency of source

PART A) Replacing our values we have that,

$f_0 = (\frac{v+v_0}{v-v_s})f_s$

$f_0 = (\frac{344+0}{344-23})(412)$

$f_0 = 441.52Hz$

PART B) Here the same procedure is performed but this time repeated in the opposite direction.

$f_0 = (\frac{v+v_0}{v-v_s})f_s$

$f_0 = (\frac{344+23}{344-0})(420)$

$f_0 = 448.08Hz$

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3 years ago

A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the

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I think its "a". but im not sure.

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3 years ago

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Earth quakes near the California Bay typically occur at frequencies of 1.5HZ or 2.8HZ. If you were engineering a new building in

jekas [21]

Answer:

2.0 Hz

Explanation:

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Answer:

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3 years ago

a grinding wheel is initially rotating with an angular velocity 5500 rad/srad/s when its motor is suddenly turned off. it comes

kiruha [24]

The angle through which the grinding wheel rotates in the first second = <u>5300 rad</u>

Angular velocity is, the time charge at which an object rotates, or revolves, about an axis, or at which the angular displacement between our bodies changes. within the discern, this displacement is represented via the angle θ among a line on one body and a line on the alternative.

The angular velocity is described as the charge of trade of the angular position of a rotating body. Linear speed is defined because the charge of change of displacement with respect to time whilst the item moves alongside a straight course.

Initial angular velocity of the grinding wheel = ω1 = 5500 rad/s

Final angular velocity of the grinding wheel = ω2 = 0 rad/s (Comes to rest)

Time is taken by the grinding wheel to come to rest = T = 10 sec

Angular acceleration of the grinding wheel = α

2 = ω1 + αT

0 = 5500 + α(10)

α = - 400 rad/s2

Negative as it is deceleration.

The angle through which the grinding wheel rotates in the first second = θ

Time period = T1 = 1 sec

θ = ω₁T1 + αT1²/2

θ = (5500)(1) + (-400)(1)²/2

θ = 5300 rad

The angle through which the grinding wheel rotates in the first second = <u>5300 rad</u>

Learn more about angular velocity here:-brainly.com/question/6860269

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1 year ago