Answer:
= +3,394 103 m / s
Explanation:
We will solve this problem with the concept of the moment. Let's start by defining the system that is formed by the complete rocket before and after the explosions, bone with the two stages, for this system the moment is conserved.
The data they give is the mass of the first stage m1 = 2100 kg, the mass of the second stage m2 = 1160 kg and its final velocity v2f = +5940 m / s and the speed of the rocket before the explosion vo = +4300 m / s
The moment before the explosion
p₀ = (m₁ + m₂) v₀
After the explosion
pf = m₁ + m₂ 
p₀ = [texpv_{f}[/tex]
(m₁ + m₂) v₀ = m₁ + m₂
Let's calculate the final speed (v1f) of the first stage
= ((m₁ + m₂) v₀ - m₂ ) / m₁
= ((2100 +1160) 4300 - 1160 5940) / 2100
= (14,018 10 6 - 6,890 106) / 2100
= 7,128 106/2100
= +3,394 103 m / s
come the same direction of the final stage, but more slowly
because crystals in granite had more time to form as magma cooled slowly. Crystals that form on the surface are smaller because they cooled really quickly
Answer:
yes.
Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed.
Explanation:
16 km/ 60 minutes = 0.26 km/min
0.26 km/min (15 min) = 4km
Explanation :
It is given that,
Length of silicon bar, 
Free electron density, 
Hole density, 
The total current flowing in bar is the sum of drift current due to hole and the electrons.
where, n and p are electron and hole densities.
![J=Eq[n\mu_n+p\mu_p]](https://tex.z-dn.net/?f=J%3DEq%5Bn%5Cmu_n%2Bp%5Cmu_p%5D)
we know that 
So, ![J=\dfrac{V}{l}q[n\mu_n+p\mu_p]](https://tex.z-dn.net/?f=J%3D%5Cdfrac%7BV%7D%7Bl%7Dq%5Bn%5Cmu_n%2Bp%5Cmu_p%5D)
![J=\dfrac{1.6\times 10^{-19}\ C}{0.001\ V}[104\ cm^{-3}\times 1200\ cm^2/V\ s+1016\ cm^{-3}\times 500\ cm^2/V\ s]](https://tex.z-dn.net/?f=J%3D%5Cdfrac%7B1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C%7D%7B0.001%5C%20V%7D%5B104%5C%20cm%5E%7B-3%7D%5Ctimes%201200%5C%20cm%5E2%2FV%5C%20s%2B1016%5C%20cm%5E%7B-3%7D%5Ctimes%20500%5C%20cm%5E2%2FV%5C%20s%5D)
or
Current, 
A is the area of bar, 
So, 
Current, 
<em>So, the current flowing in silicon bar is </em>.
