
all we can really cancel is one of the (x-5) and the "x", is all.
For this case we must find the solution of the following quadratic equation:

Where:

Then, the solution is given by:

Substituting the values:

By definition we have:

Thus, we have two complex roots.
Answer:
The equation has no real roots.
2/5 is the answer unless your multiplying
Answer:
c = (b+3a)/2
Step-by-step explanation:
<u>Solve for c:</u>
<u>Multiply both sides by abc:</u>
- abc/ac = 2abc/ab - 3abc/bc
- b = 2c - 3a
- b + 3a = 2c
- 2c = b + 3a
- c = (b + 3a)/2
Answer: Attached.
Step-by-step explanation:
Either solve the equations directly, or graph them and look for the point of intersection.