Answer:
Lines c and b, f and d (option b)
Step-by-step explanation:
To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -
Option 1:
Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.
Option 2:
All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.
Option 3:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
Option 4:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
I hope this helps, it’s a bit messy but yeahh
Answer:
3m + 2 ≤ 20
Step-by-step explanation:
Since they only have $20 and CANNOT go over it, the inequality would be ≤ 20
3m + 2 ≤ 20
Perhaps the most concise way to factor is by "completing the square" which is how the quadratic formula is derived...
x^2+6x+8=0 move constant to other side, subtract 8 from both sides
x^2+6x=-8, halve the linear coefficient, square it, then add that to both sides, in this case (6/2)^2=3^2=9
x^2+6x+9=1 now the left side is a perfect square of the form
(x+3)^2=1 take the square root of both sides
x+3=±√1 subtract 3 from both sides
x=-3±√1
x=-3±1
x=-4 and -2
Since the zeros occur when x=-4 and -2 the factors of the equation are:
(x+2)(x+4)
