Well for each pair of x and y value of the table, you can always find the coordinates of that point on the graph.
eg. x=y=-2 you can find the point {-2,-2} on the graph
First, let's take a look at the formula to figure this out.
m = y2 - y1/x2 - x1
y2 would be -5, and y1 would be 8. -5 - 8 = -13.
x2 is -6, and x1 is also -6. -6 - -6 would be -12.
So, now we must divide -13 and -12, which results in 1 1/12.
You need to split the shape into two then measure the shapes like trapezoids use a+b/2(h) for the formula
Answer:
![\int_{-\infty}^0 5 e^{60x} dx = \frac{1}{12}[e^0 -0]= \frac{1}{12}](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7B1%7D%7B12%7D%5Be%5E0%20-0%5D%3D%20%5Cfrac%7B1%7D%7B12%7D)
Step-by-step explanation:
Assuming this integral:
We can do this as the first step:
Now we can solve the integral and we got:
![\int_{-\infty}^0 5 e^{60x} dx = \frac{e^{60x}}{12}\Big|_{-\infty}^0 = \frac{1}{12} [e^{60*0} -e^{-\infty}]](https://tex.z-dn.net/?f=%20%5Cint_%7B-%5Cinfty%7D%5E0%205%20e%5E%7B60x%7D%20dx%20%3D%20%5Cfrac%7Be%5E%7B60x%7D%7D%7B12%7D%5CBig%7C_%7B-%5Cinfty%7D%5E0%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Be%5E%7B60%2A0%7D%20-e%5E%7B-%5Cinfty%7D%5D)
So then we see that the integral on this case converges amd the values is 1/12 on this case.
A Rectangle Is A 4 Sided Closed Figure That Has 4 Right Angles, While A Rhombus Does Not Have Any Right Angles
