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3 years ago

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Eduardo used fabric to make three costumes. he used 1/4 yard for first then 2/4 yard for the second and 3/4 yard for the third c

ostume. how much fabric did Eduardo use all together

1 answer:

Dmitry [639]3 years ago

6 0

add the fractiosn together, since they all have the same denominator, simply add the numerators
1/4+2/4+3/4=6/4
or
1 1/2 yards of fabric (2/4 = 1/2)

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The perimeter of a rectangle is 72 in. The base is 3 times the height. Find the area of the rectangle

Dovator [93]

Answer:

243 in²

Step-by-step explanation:

Step 1. Calculate the<em> base and height </em>of the rectangle

We have two conditions:

(1) 2b+ 2h = 72 in

(2) b = 3h Substitute in (1)

2(3h) + 2h = 72 Remove parentheses

6h + 2h = 72 Combine like terms

8h = 72 Divide by 6

h = 9 in Substitute in(2)

b = 3 × 9

b = 27 in

Step 2. Calculate the area of the rectangle

A = bh

A = 27 × 9

A = 243 in²

The area of the rectangle is 243 in².

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3 years ago

Carley beat the school record for the 400 meter run by 1.3 seconds. If she ran the race in 55.7 seconds, what was the record.

dybincka [34]

Answer:

57 seconds

Step-by-step explanation:

55.7 + 1.3 = 57 seconds

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2 years ago

-3(x + 4) = (-x - 1)

zaharov [31]

Answer:

x=-5.5

Step-by-step explanation:

-3(x+4)=(-x-1)

1. Distribute

-3x+(-12)=-x-1

2. Simplify

-3x-12=-x-1

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Answer:

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2 years ago

Find a linear second-order differential equation f(x, y, y', y'') = 0 for which y = c1x + c2x3 is a two-parameter family of solu

Alisiya [41]

Let $y=C_1x+C_2x^3=C_1y_1+C_2y_2$ . Then $y_1$ and $y_2$ are two fundamental, linearly independent solution that satisfy

$f(x,y_1,{y_1}',{y_1}'')=0$
$f(x,y_2,{y_2}',{y_2}'')=0$

Note that ${y_1}'=1$ , so that $x{y_1}'-y_1=0$ . Adding $y''$ doesn't change this, since ${y_1}''=0$ .

So if we suppose

$f(x,y,y',y'')=y''+xy'-y=0$

then substituting $y=y_2$ would give

$6x+x(3x^2)-x^3=6x+2x^3\neq0$

To make sure everything cancels out, multiply the second degree term by $-\dfrac{x^2}3$ , so that

$f(x,y,y',y'')=-\dfrac{x^2}3y''+xy'-y$

Then if $y=y_1+y_2$ , we get

$-\dfrac{x^2}3(0+6x)+x(1+3x^2)-(x+x^3)=-2x^3+x+3x^3-x-x^3=0$

as desired. So one possible ODE would be

$-\dfrac{x^2}3y''+xy'-y=0\iff x^2y''-3xy'+3y=0$

(See "Euler-Cauchy equation" for more info)

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3 years ago