The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
To find the answer to a problem like this, we need to look for patterns in the number!
It looks likes x = 2y
Or in other words, (y is being multiplied by 2 to find x!)
**Now that we've discovered this pattern, we can confidently say that ...
<u>the number</u><u> 6</u><u> belongs in</u><u> #1 </u>
Answer:
Step-by-step explanation:
You need the value of one of angles. If height angle is 90°, then you have 2 90° angles. So you have 2 triangles SAS.
I hope I've helped you.
