Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
The answer is 35
Explanation: because 42 divided by 6 is 7 and 7 times 5 is 35
9514 1404 393
Answer:
C
Step-by-step explanation:
Corresponding angles are listed in the same order in the mapping statement.
C' is the third vertex named in A'B'C'D'. It corresponds to the third vertex named in ABCD, which is C.
angle C' corresponds to angle C
Answer:
The probability of a customer buying carrots is 0.10.
Step-by-step explanation:
Here, given:
P (Customer buying apples) = 12%
⇒ P(A) = 12 \100 = 0.12
P(Customer Buying apples AND Carrots) = 5%
⇒ P(A ∩ C ) = 5 /100 = 0.05
P(Customer buying apples OR carrots ) = 17%
⇒ P(A∪ C) = 17/100 = 0.17
Now, we know that:
<h3>
P(X ∪ Y) = P(X) + P(Y) - P(X ∩ Y ) </h3><h3>
</h3>
Now, here substituting the values, we get:
P(A∪ C) = P(A) + P(C) - P(A ∩ C )
⇒ 0. 17 = 0.12 + P(C) - 0.05
or, 0.17 - 0.07 = P(C)
or, P(C) = 0.10
or, P(Customer Buying Carrots) = 0.10
Hence, the probability of a customer buying carrots is 0.10.
