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marshall27 [118]
2 years ago
11

If <2 and <3 are complementary how could you use the vertical angle theorem to find m<1

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0

for solving equations such as this chrome would be the best thing n

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I need help please!!
geniusboy [140]

the first answer is correct

7 0
3 years ago
Read 2 more answers
A dog weighs 35.4 kilograms.1 kilogram=2.2 pounds,1 pound=0.45 kilograms.About how much does the dog weigh in pounds?Round to ne
AlladinOne [14]
Answer: 78 pounds
Explanation: if 1 kilogram is 2.2 pounds, just multiply the weight in kg by 2.2:
35.4 x 2.2 = 77.88
Round to nearest whole: 78.
So the dog is 78 pounds
4 0
2 years ago
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<img src="https://tex.z-dn.net/?f=%203%20000%20000%5E%7B2%7D%20%20" id="TexFormula1" title=" 3 000 000^{2} " alt=" 3 000 000^{2
Pachacha [2.7K]
{3000000}^{2} + {4000000}^{2} \\ \\ {10}^{6} ( {3}^{2} + {4}^{2} ) \\ \\ {10}^{6} \times 25 \\ \\ 25000000 \: \: \: \: \: Ans.
8 0
3 years ago
*WILL GIVE BRAINLIEST ANSWER* Analyze the graph. Determine what, if any, association there is. Explain. On a graph, points are g
Gnesinka [82]

Answer:

bro I thought someone else answered your question

4 0
2 years ago
What’s the answer??(SOMEONE PLEASE HELP ME)
Evgesh-ka [11]

To find f^{-1}, you can switch the "x" and "f(x) or y" in the equation.

f(x) = \sqrt[3]{x-2} +8

y = \sqrt[3]{x-2}+ 8

x = \sqrt[3]{y-2}+8

Now you need to isolate the "y"

x = \sqrt[3]{y-2}+8   Subtract 8 on both sides

x - 8 = \sqrt[3]{y-2}  Cube ( ³ ) each side to get rid of the ∛

(x-8)^{3} = (\sqrt[3]{y-2}) ^{3}

(x-8)^{3} = y -2   Add 2 on both sides

(x-8)^{3}+2 = y


f^{-1} = (x-8)^{3} + 2


5 0
3 years ago
Read 2 more answers
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