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Murljashka [212]
3 years ago
12

What are the least common multiples of 7 and 11

Mathematics
1 answer:
Luda [366]3 years ago
3 0
I think is the least common number is 77 because it multiple of 7 and 11 both
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I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

7 0
3 years ago
On a given blueprint, 1 inch = 30 feet. If the dimensions of a meeting room on the blueprint are 1.5 inches x 1.25 inches, what
melamori03 [73]
Sounds simple to me but may be misleading, I can't see a trick.
I think all you do is multiply each by 30.

So answer is 45ft X 37.5ft

Hope it's correct. I'd appreciate if you could let me know. Thks..
6 0
3 years ago
What is the biggest decimal and take away two​
tensa zangetsu [6.8K]

Answer:

about -1

Step-by-step explanation:

0.9999999999 minus 2

3 0
3 years ago
DFG and JKL are complementary angles. M DFG = x+5 and m JKL=x-9. The measure of DFG is ___, and the measure of JKL is ___.
jeyben [28]

Answer:

C

Step-by-step explanation:

the sum of complementary angles = 90°, hence

x + 5 + x - 9 = 90

2x - 4 = 90 ( add 4 to both sides )

2x = 94 ( divide both sides by 2 )

x = 47

Thus ∠DFG = 47 + 5 = 52° and ∠JKL = 47 - 9 = 38°


6 0
3 years ago
Read 2 more answers
Help plz i need it :(
mr_godi [17]

Answer:

B.

C.

D.

E.

Step-by-step explanation:

6 0
3 years ago
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