Question

How many solutions are there to the following system of equations?

Answer 1

$-4x-8y=0\\ \underline{-3x+8y=-7}\\ -7x=-7\\ x=1 \Rightarrow B$

Answer 2

$4x-8y=0 \\ \underline{-3x+8y=-7} \\ 4x-3x=0-7 \\ x=-7 \\ \\ 4x-8y=0 \\ 4 \times (-7)-8y=0 \\ -28-8y=0 \\ -8y=28 \\ y=\frac{28}{-8} \\ y=-\frac{7}{2} \\ \\ \left \{ {{x=-7} \atop {y=-\frac{7}{2}}} \right.$

There is one solution to this system of equations. The answer is B.