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riadik2000 [5.3K]

3 years ago

10

How many solutions are there to the following system of equations?

2 answers:

Bas_tet [7]3 years ago

7 0

$-4x-8y=0\\
\underline{-3x+8y=-7}\\
-7x=-7\\
x=1 \Rightarrow B$

sweet [91]3 years ago

6 0

$4x-8y=0 \\
\underline{-3x+8y=-7} \\
4x-3x=0-7 \\
x=-7 \\ \\
4x-8y=0 \\
4 \times (-7)-8y=0 \\
-28-8y=0 \\
-8y=28 \\
y=\frac{28}{-8} \\
y=-\frac{7}{2} \\ \\
 \left \{ {{x=-7} \atop {y=-\frac{7}{2}}} \right.$

There is one solution to this system of equations. The answer is B.

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