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dalvyx [7]
3 years ago
8

The reactants of two chemical equations are listed.

Chemistry
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

equation 1: AgNo3 + Zn is the reaction because of the zinc

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Which best describes why a liquid needs a container when a solid does not?
vitfil [10]

liquid is fluid in motion, needing to be contained. while a solid state of matter is as such and won't run down the cabinet

4 0
3 years ago
Read 2 more answers
Given a compound with a mw of 169 amu having 13.60% na, 8.29% n, 35.51% c, 4.77% h, and 37.85% o, determine the number of each a
Arisa [49]
1) Percent composition

<span>Na: 13.60%,
N:     8.29%
C:    35.51%
H:      4.77%
O:   37.85%
     -------------
       100.02%

2) Convert mass percent to molar composition

For that, divide the percent of each element by its atomic mass.

</span>
<span>Na: 13.60 / 22.99 = 0.5916
N:     8.29 / 14.01 = 0.5917
C:    35.51 / 12.01 = 2.9567
H:      4.77 / 1.01 = 4.7228
O:   37.85 / 16.00 = 2.3656

3) Divide each number by the smallest one:

</span>
<span><span>Na:  0.5916 / 0.5916 = 1.0
N:     0.5917 / 0.5916 = 1.0
C:    2.9567 / 0.5916 = 5.0
H:      4.7228 / 0.5916 = 8.0
O:   2.3656</span> / 0.5916 = 4.0

4) State the empirical formula: Na N C5 H8 O4

5) Calculate the mass of the empirical formula:

Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.

1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13

6) Divide the molar mass by the mass of the empirical formula:

169 / 169.13 = 1

7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:

Na: 1
N: 1
C: 5
N: 8
O: 4
</span>

5 0
3 years ago
Read 2 more answers
PREDICT Do you think warming a cannonball in a fire has any effect
Zanzabum
I think yes because the heat from the fire will transferred to the cannon ball and it will cause something with its energy to change effect.
5 0
2 years ago
If the reaction of 150. G of ammonia with 150. G of oxygen gas yields 87. G of nitric oxide (no), what is the percent yield of t
Gekata [30.6K]

The percentage yield of the given reaction is 77.33%.

What is percentage yield?
Reactants
frequently produce fewer product quantities than predicted by the chemical reaction's formula. The percentage of a theoretical yield that's been produced in a reaction is calculated using the percent yield formula. Working through a stoichiometry problem yields the theoretical yield, which is the ideal quantity of the final product. The actual yield is determined by calculating the volume of the product formed. We can determine the percentage yield by dividing the actual yield by the theoretical yield.

Moles is calculated by using the formula:
Moles of Ammonia:
Given mass of ammonia = 150g
Molar mass of ammonia = 17 g/mol
Putting values in above equation, we get:

Moles of Oxygen
Given mass of oxygen = 150g
Molar mass of oxygen = 32 g/mol
Putting values in above equation, we get:
For the given chemical equation:

By Stoichiometry,
5 moles of oxygen reacts with 4 moles of ammonia.
So, 4.6875 moles of oxygen will react with =  of ammonia
As, moles of ammonia required is less than the calculated moles. Hence, ammonia is present in excess and is termed as excess reagent.
Therefore, oxygen is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the given reaction:
5 moles of oxygen gas produces 4 moles of nitric oxide
So, 4.6875 moles of oxygen gas will produce =  of nitric oxide

Now, to calculate the theoretical amount of nitric oxide, we use equation 1: Molar mass of nitric oxide = 30 g/mol
 Given mass of nitric oxide = 112.5 g
Now, to calculate the percentage yield, we use the formula:
Experimental yield = 87 g
Theoretical yield = 112.5 g
Putting values in above equation, we get:
Hence, the percentage yield of the given reaction is 77.33%.

learn more about percentage yield
brainly.com/question/14714924
#SPJ4

6 0
1 year ago
The Henry's law constant for helium gas in water at 30 °C is 3.70 × 10-4 M/atm. When the partial pressure of helium above a samp
igor_vitrenko [27]

Answer:

The concentration of helium in the water is 2.405×10^-4 M

Explanation:

Concentration = Henry's law constant × partial pressure of helium

Henry's law constant = 3.7×10^-4 M/atm

Partial pressure of helium = 0.65 atm

Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M

4 0
3 years ago
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