The compound HNO3 is called nitric acid.
HNO3 is a covalent compound and a strong acid which ionizes in water into H+ (proton) and NO3- (nitrate ion).
HNO3 (aq) ↔ H+(aq) + NO3-(aq)
Ans: HNO3 = Nitric Acid
[On a side note: Nitrous acid is HNO2]
The volume of carbon dioxide produced is : 5.4 L
<u>Given data:</u>
moles of propane = 0.080 moles
<h3>Determine the volume of Carbon dioxide produced </h3>
The chemical reaction
C₃H₈ + 5O₂ ---- > 3CO₂ + 4H₂O
From the reaction
I mole of C₃H₈ = 3CO₂
0.080 moles of C₃H₈ = 3 * 0.080 = 0.24
Applying the equation below to determine the volume of CO₂
Pv = nRT
= 0.24 * R * T
v = ( 0.24 * 8.314 * 273 ) / 1 atm
= 544.7 ml = 5.4 L
Hence we can conclude that The volume of carbon dioxide produced is : 5.4 L
Learn more about Propane burning at STP : brainly.com/question/11903456
<u>Answer:</u> The percent composition of in taconite is 37.6 %.
<u>Explanation:</u>
We are given:
Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)
Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )
We know that:
Molar mass of iron = 55.85 g/mol
Molar mass of = 231.53 g/mol
1 mole of contains 3 moles of iron atom and 4 moles of oxygen atom
(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of
So, 247212 grams of iron will be produced from = of
To calculate the percentage of in taconite, we use the equation:
Mass of taconite = 907185 g
Mass of = 341611.43 g
Putting values in above equation, we get:
Hence, the percent composition of in taconite is 37.6 %.
Hydrogen fuses into helium