I think probably not because everybody has a very different handspan and you probably wouldn't be able to get a very accurate average.
Answer:
h[j(3)] = -20
Step-by-step explanation:
We need h(j(3)). First find j(3)
j(x) = -x, so
j(3) = -(3) = -3
Now find h(-3)
h(x) = 4x - 8, so
h(-3) = 4(-3) - 8
h(-3) = -12 - 8 = -20
So h[j(3)] = -20
Answer:
d.
I and IV only.
Step-by-step explanation: