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3 years ago

The touchdown to fumble ratio for Bobby Boucher was 9:2 If Bobby ran for 18 touchdowns,

Mathematics

1 answer:

Vika [28.1K]3 years ago

4 0

Answer: He had 14 more touchdowns than he did fumbles.

Step-by-step explanation:

Step 1. Ok, so we need to see how many times 9 will divide into 18.

18/9=2.

Step 2. So now that we know that 9 goes into 18 two times and we know he has two fumbles for every 9 touchdowns we can multiply 2 by 2 to find out how man fumbles he had.

2*2=4

Step 3. Now to find out how many more touchdowns than fumbles he had we need to subtract his fumbles from his touchdowns.

18-4= 14. So, now we know he had 14 more touchdowns than he did fumbles.

Hope this helps!

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Learn with an example Find the perimeter. Simplify your answer. y-6 y-5 y-5 y-6

koban [17]

Answer:

P = 22

Step-by-step explanation:

P= l(2) + w(2)

5(2) + 6(2)

10 + `12

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3 years ago

You cut a 54-inch rope into four pieces. Twoof the pieces are the same length, a thirdpiece is twice as long as each of the twoe

antiseptic1488 [7]

Let's use the variable x to represent the length of the first and second pieces.

If the third piece has twice the length of the first and second, its length is 2x.

If the fourth piece has half the length of the first and second, its length is 0.5*x.

Adding all four pieces and equating to 54 inches, we have:

$\begin{gathered} x+x+2x+0.5x=54 \\ 4.5x=54 \\ x=\frac{54}{4.5} \\ x=12 \end{gathered}$

So the length of each piece is:

12 inches, 12 inches, 24 inches and 6 inches.

5 0

1 year ago

What is the twentieth term of the arithmetic sequence 21, 18, 15, 12, ... ?

Vaselesa [24]

Answer:

-36

Step-by-step explanation:

21, 18, 15, 12....

All you have to do is subtract 3 less on each number you get, until u get to the twentieth term....

21, 18, 15, 12, 9, 6, 3, 0, -3, -6, -9, -12, -15, -18, -21, -24, -27, -30, -33, -36

-36 is the twentieth term of this arithmetic sequence

Hope this helped!

Have a supercalifragilisticexpialidocious day!

8 0

2 years ago

Two life insurance policies, each with a death benefit of 10,000 and a one-time premium of 500, are sold to a couple, one for ea

Kazeer [188]

Answer:896.9

Step-by-step explanation:

Let x denotes excess premium over claims

$E\left ( x|husband survives\right )$ , There are two possibilities

(i)Only husband survives

This can be possible with a possibility of 0.01

Claims=10,000

Premium collected $=2\times 500=1000$

Thus x=1000-10,000=-9000

(ii)Both husband and wife survives

This can occur with a probability of 0.96

Here claims will be 0 as both survives

Premium taken=1000

thus x=1000

The probability that the husband survives is the sum of above cases

=0.96+0.01=0.97

Hence the desired conditional Expectation $E\left ( x|Husband survives\right ) =0.01\times \left ( -9000\right )+0.96\times \left ( 1000\right )=896.9$

7 0

3 years ago

Please help me with this

natali 33 [55]

Your answer would be 5

8 0

3 years ago

Read 2 more answers