The value of x is 15° and the type of quadrilateral is a rhombus.
<h3>
Quadrilateral</h3>
- A quadrilateral is a polygon that has four sides.
- The sum of all angles of a quadrilateral is 360°.
Here, we are given,
m∠A = (7x)◦, m∠B = (4x + 5)◦, m∠C =(6x + 15)◦, m∠D = (6x −5)◦
So, we will have
7x+4x+5+6x+15+6x-5=360°
23x+15°=360°
23x=345°
x=345°/23°
x=15°
Hence, the angles of the quadrilateral are:
m∠A = (7x)◦=105°,
m∠B = (4x + 5)◦ =65°
m∠C =105°
m∠D = (6x −5)◦ =85°
Since the diagonal bisects ∠B and ∠D, we get that the quadrilateral is a rhombus.
To learn more about rhombus refer to:
brainly.com/question/27870968
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Answer:
74 feet and 6 feet
Step-by-step explanation:
Mentioned that
The Length of the dog park is = (8x + 2)............(i)
And,
The Width of the park is = (2x -12)..................(ii)
Perimeter = 160 feet
Now here we use the perimeter formula which is
Perimeter is
= 2 (length + width)
160 = 2 (8x + 2 + 2x - 12)
160 = 2 (10x - 10)
160 = 20x - 20
180 = 20x
x = 9
Now put the x value into the equation 1 and equaton 2
For the equaton 1, the length us
= 8x + 2
= 8(9) + 2
= 74 feet
And, the width is
= 2x - 12
= 2(9) - 12
= 18 - 12
= 6 feet
60 + 3x = 180 ( linear pair)
3x = 180 - 60
3x = 60
x = 60/3
x = 20
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the point of intersection on the graph are (3,-2)