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Gnesinka [82]
3 years ago
5

Look at attachment inside please help me im on timer

Mathematics
1 answer:
Julli [10]3 years ago
3 0

4x { }^{2}  + 5 +  \frac{27}{x + 5}
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Solve px-18=4 for x ​
sashaice [31]

Answer:

x=22/p

Step-by-step explanation:

1. Add 18 to 4

2. px=22

3. Divide by p to isolate x

4. 22/p=x

4 0
3 years ago
Read 2 more answers
Please help me .............
borishaifa [10]

Answer:

The first one.

Step-by-step explanation:

For something to be considered to be a graph, every x value must have 1 y value. It does not matter if y values are the same, but you MUST make sure there is ONLY ONE of each value. So for example the second one wouldn't be a function because -5 appears twice for the x values, but with different y values. This would mean when graphed, it would fail the vertical line test (if you put a vertical line anywhere on the graph you will only get one point).

8 0
2 years ago
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5
podryga [215]

Answer:

C-7.4

Step-by-step explanation:

just took the test EDG2020

3 0
3 years ago
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A study was performed with a random sample of 5 people from a certain city. What population would be appropriate for generalizin
Schach [20]

Answer:

The conclusions apply only to the sample.

Step-by-step explanation:

Since the sample size is small, it's not likely to be representative of any larger population.

I hope this helps!

7 0
3 years ago
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The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports
harkovskaia [24]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the T test output :

T-Test

μ<4.00

t=-3.033077

p=0.002025

x=3.48

Sx=1.150075

n=45

Given that population mean, μ = 6

Confidence level, α = 0.05

The hypothesis :

H0 : μ = 6.00

H1 : μ < 6.00

From the t test output given :

The test statistic :

T = -3.033077

T = - 3.03 (2 decimal places)

The Pvalue :

P = 0.002025

Pvalue = 0.002 (3 decimal places)

The conclusion :

Decision region ; Reject H0 : if Pvalue < α

Since ; Pvalue < α

Reject H0 ; There is sufficient evidence to support claim that sample is from a population with a mean less than 6.

4 0
2 years ago
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