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7nadin3 [17]
3 years ago
15

PLEASE HELPPPPPP!!!!!!Solve this system of linear equations separate the x-and y-values with a comma

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

x=-6,\\y=6

Step-by-step explanation:

Rewrite the system of equations as:

\begin{cases}-13x+2y=90\\-6x+2y=48\end{cases}

Subtract the second equation from the first to isolate x:

-13x+2y-(-6x+2y)=42,\\-7x=42, \\\fbox{$x=-6$}

Plug in x=-6 into any of the equations above and solve for y:

-6(-6)+2y=48,\\2y=12,\\\fbox{$y=6$}

Verify that the solution pair (-6, 6) works \checkmark

Therefore, the solution to this system of equations is:

x=-6,\\y=6

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Read 2 more answers
there are 153 people in line for a ride at an amusement park the ride can take 40 people at a time how many times will the ride
krek1111 [17]

Answer:

Step-by-step explanation:

we need to divide

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8 0
3 years ago
The proportions of blood types O, A, B, and AB in the general population of a particular country are known to be in the ratio 49
Morgarella [4.7K]

Answer:

The proportions differ significantly from those in the general population.

Step-by-step explanation:

We state our null and alternative hypotheses as

H0: p1= 49/100, p2= 38/100, p3= 9/100 and p4= 4/100 for a multinomial distribution involving four categories and n= 170

against

Ha: pi≠ pi0 for at least one value of i= 1,2,3,4

The significance level is set at ∝= 0.05

The test statistic under H0 is

χ² = ∑ (Oi- ei)²/ei

which has approximate chi square distribution with 3d.f  (n-1)

Computations: Under H0 the expected frequencies are

np10= Blood type O = 170 * 49/100= 83.3

np20 = Blood type A = 170 * 38/100= 64.6

np30 = Blood type B = 170 * 20/100= 11.76

np40 = Blood type AB = 170 * 4/100= 2.35

The value of χ² is computed as follows

Cell       Observed         Estimated        (Oi-ei)            (Oi-ei)²   (Oi-ei)²/ei

             Frequency      Frequency  

               Oi                    ei

1             87                        83.3               3.7               13.69        0.157

2            59                      64.6              -5.6                 31.36       0.531

3             20                     34                  -14                   196           9.8

<u>4               4                      6.8                -2.8                  7.84         1.96       </u>

<u>∑             170                    188.7                                                  χ²= 12.43  </u>

<u />

The critical region is <u>χ</u>²≥ χ²(0.05,3) = 7.82 for alpha = 0.05 and

<u>χ</u>²≥ χ²(0.01,3) = 11.34  for alpha = 0.01

As the calculated value lies in the critical region for both value of alpha we reject our null hypothesis and accept our alternate hypothesis. The proportions differ significantly from those in the general population.

6 0
3 years ago
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