2 years ago

PLEASE HELP!! What is the inverse of f(x) = (5x + 2)² for x ≥ -2/5

Mathematics

1 answer:

77julia77 [94]2 years ago

5 0

Answer:

its sqrt(x)/5-2/5, x is greater than or equal to 0

Step-by-step explanation:

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Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

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Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

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PLEASE HELP!! What is the inverse of f(x) = (5x + 2)² for x ≥ -2/5​

PLEASE HELP!! What is the inverse of f(x) = (5x + 2)² for x ≥ -2/5