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olya-2409 [2.1K]
3 years ago
12

Y = 3x +1; domain = {-1, 0, 1} Help me find range value

Mathematics
1 answer:
Xelga [282]3 years ago
7 0

We have to put values of domain to find range

\\ \ast\sf\longmapsto y=3x+1

\\ \ast\sf\longmapsto D_R=[-1,0,1]

\\ \ast\sf\longmapsto y=3(-1)+1=-3+1=-2

\\ \ast\sf\longmapsto y=3(0)+1=0+1=1

\\ \ast\sf\longmapsto y=3(1)+1=3+1=4

Now

\\ \ast\sf\longmapsto R_R=[-2,1,4]

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3 years ago
The function below is defined for all x except one value of x. If possible, define f(x) at the exceptional point in a way contin
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Answer:

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Step-by-step explanation:

for the function

F(x) = x² - 13*x + 22/x-11 , for x ≠ 11

then in order to define F(x=11) so  F is continuous (see Note below) . By definition of continuity of a function:

F(x) is continuous in x=11 if lim F(x)=F(a) when x→a

then

when x→a , lim x² - 13x + 22/x-11 = lim 11² - 13*11 + 22/11 -11 = -3*11 + 2 = -31 = F(x=11)

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F is not continuous in all x since

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when x→0⁻,  lim (0⁻) ² - 13*0⁻  + 22/0⁻ -11 = (-∞)

then

limit F(x) , when x→0 does not exist since the limit from the left and from the right do not converge → since the limit does not exist , the function is not continuous  in x=0

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