6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96 so 20 6's
-19/15
you multiply boh sides by the other denomonater
-10 and -9
15 15
Answer:
Step-by-step explanation:
y = 9 - X is a linear function; x is to the first power.
y = x2 + 1 does NOT represent a linear function; it's a quadratic function.
o
y=x² + 5 does NOT represent a linear function; it's a quadratic function.
D)
y = [xl - 9 does NOT represent a linear function; it's an absolute value function. This function has two halves, each of which is a linear function.
But the best answer here is that y = 9 - X is a linear function; x is to the first power.
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
