49: 1 7, 49
84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
The GCF is 7
Answer:
1/9, 2/9, 3/9, 4/9, 1/8, 2/8, 3/8, 1/7, 2/7, 3/7, 1/6, 2/6, 1/5, 2/5, 1/4, 1/3.
Step-by-step explanation:
hope this helps,
Answer:
The distance of the object from the base of cliff is 18.24 meters
Step-by-step explanation:
Given as :
The height of the vertical cliff = h = 50 meters
The distance of the object from the base of cliff = x meters
Let The angle of depression of object that level with cliff base = Ф = 70°
<u>Now, from figure</u>
Tan angle = 
I.e TanФ = 
Or, TanФ = 
Or, Tan 70° = 
Or, 2.74 = 
∴ x =
I,e x = 18.24 meters
So, The distance of the object from the base of cliff = x = 18.24 meters
Hence,The distance of the object from the base of cliff is 18.24 meters Answer
The mode of the given data is equal to bowls of spaghetti.
<u>Given the following data:</u>
- Quantity of sandwiches = 14.
<h3>What is mode?</h3>
In Mathematics, a mode can be defined as a statistical terminology that is used to denote the value that appears most often or repeatedly occurring in a given data set.
This ultimately implies that, a mode represents the value (number) with the highest frequency. In this exercise, the bowls of spaghetti represents the mode of the given data.
Read more on mode here: brainly.com/question/542771
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)