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SashulF [63]
2 years ago
9

Work out a) 5 3/4- 2 1/4

Mathematics
2 answers:
xxTIMURxx [149]2 years ago
7 0

Answer:

The answer is 3 1/2.

Step-by-step explanation:

-There are 2 simple ways to do this.

-The first is just subtracting 3/4 and 1/4 which equals 2/4 or 1/2.

-The second way is to turn it into an improper fraction.

-(5*4)+3=23 and (2*4)+1=9.

-23/4-9/4=14/4

-14/4=3 1/2

xenn [34]2 years ago
3 0

Answer:

3 1/4

Step-by-step explanation:

5 3/4 - 2 1/4

First subtract the whole numbers of the two mixed fractions, so:

= 5 - 2

= 3

Now, combine the leftover fractions:

= 3/4 - 1/4

= 2/4

= 1/4

Lastly, put the whole number and fraction together:

= 3 1/4

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What is the greatest common factor of 49 and 84? 3 4 7 9
bonufazy [111]
49: 1 7, 49
84: 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84

The GCF is 7
6 0
3 years ago
Read 2 more answers
Which fraction is close to, but less than 1/2?
qwelly [4]

Answer:

1/9, 2/9, 3/9, 4/9, 1/8, 2/8, 3/8, 1/7, 2/7, 3/7, 1/6, 2/6, 1/5, 2/5, 1/4, 1/3.

Step-by-step explanation:

hope this helps,

8 0
3 years ago
From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°
Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

I.e TanФ = \dfrac{\textrm AB}{\textrm OA}

Or, TanФ = \dfrac{\textrm h}{\textrm x}

Or, Tan 70° = \dfrac{\textrm 50 meters}{\textrm x meters}

Or, 2.74 = \dfrac{\textrm 50}{\textrm x}

∴ x =  \dfrac{\textrm 50}{\textrm 2.74}

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

5 0
3 years ago
what is the mode of the following data: 52 bowls of spaghetti, 37 bowls of cereal, 14 sandwhiches, and 17 personal pizzas
Katarina [22]

The mode of the given data is equal to bowls of spaghetti.

<u>Given the following data:</u>

  • Bowls of spaghetti = 57.
  • Bowls of cereal = 37.
  • Quantity of sandwiches = 14.
  • Personal pizzas = 17.

<h3>What is mode?</h3>

In Mathematics, a mode can be defined as a statistical terminology that is used to denote the value that appears most often or repeatedly occurring in a given data set.

This ultimately implies that, a mode represents the value (number) with the highest frequency. In this exercise, the bowls of spaghetti represents the mode of the given data.

Read more on mode here: brainly.com/question/542771

4 0
2 years ago
I need help ASAP! It's urgent.. PLISSSSS​
natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>

\frac{4}{3}(t -24)= 28

\frac{4}{3}t - 32= 28

\frac{4}{3}t= 32 +28

\frac{4}{3}t= 60

t= 6 0\div  \frac{4}{3}

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

5 0
3 years ago
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