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3 years ago

In computer science, what does the word security mean?

Computers and Technology

1 answer:

zepelin [54]3 years ago

4 0

Answer:

Explanation:

Computer security, cybersecurity or information technology security (IT security) is the protection of computer systems and networks from information disclosure, theft of or damage to their hardware, software, or electronic data, as well as from the disruption or misdirection of the services they provide.[1]

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Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *

devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

else // check if n is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;

while(i<=(2*n))

{

sum1+= i;

i++;

}

else // check if n is negative

{

int i=n;

while(i<=(2*n))

{

sum1+= i;

i++;

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop 2 * n to n and storing the sum in "sum1" variable. Finally display sum1 variable .

4 0

3 years ago

What has global css rulesets of an angular 8 project mcq.

love history [14]

In order to conserve the angular momentum, Angular speed (w) often increases. The 'none of the above' option has global CSS rulesets of an angular 8 project mcq.

The angular momentum of a rigid object is known as the product of the moment of inertia and the angular velocity.

Angular speed is described as how quickly an object rotates. it is seen as the change in the angle of the object per unit of time.

See full question below

What has global CSS rulesets of an angular 8 project mcq.

A. e2e

B. None of the above

C. App

D. node_modules

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2 years ago

The technique of ________ uses three columns that allows the entrepreneur to weigh both the advantages and the disadvantages of

Mekhanik [1.2K]

Force-field analysis

5 0

3 years ago

(iii) If 1 GB = 2x then what is the value of x?

frez [133]

Since a Gigabyte is made of Megabytes, 500 Megabytes times 2, 2(500MB), is equal to one Gigabyte. (1000MB)
UNLESS, it wants the Windows way of storage, because one Gigabyte in Windows terms is actually 1024 megabytes... then it’d be 2(512MB) because 512MB and 512MB equals one windows storage gigabyte.

4 0

3 years ago

Write a program that accepts an integer value called multiplier as user input. Create an array of integers with ARRAY_SIZE eleme

Tasya [4]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

void PrintForward(int myarray[], int size){

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

void PrintBackward(int myarray[], int size){

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

int main(){

const int ARRAY_SIZE = 12;

int multiplier;

cout<<"Multiplier: ";

cin>>multiplier;

int myarray [ARRAY_SIZE];

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

PrintForward(myarray,ARRAY_SIZE);

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

Explanation:

The PrintForward function begins here

void PrintForward(int myarray[], int size){

This iterates through the array in ascending order and print each array element

for(int i = 0; i<size;i++){ cout<<myarray[i]<<" "; }

}

The PrintBackward function begins here

void PrintBackward(int myarray[], int size){

This iterates through the array in descending order and print each array element

for(int i = size-1; i>=0;i--){ cout<<myarray[i]<<" "; }

}

The main begins here

int main(){

This declares and initializes the array size

const int ARRAY_SIZE = 12;

This declares the multiplier as an integer

int multiplier;

This gets input for the multiplier

cout<<"Multiplier: "; cin>>multiplier;

This declares the array

int myarray [ARRAY_SIZE];

This iterates through the array and populate the array by i * multiplier

for(int i = 0; i<ARRAY_SIZE;i++){ myarray[i] = i * multiplier; }

This calls the PrintForward method

PrintForward(myarray,ARRAY_SIZE);

This calls the PrintBackward method

PrintBackward(myarray,ARRAY_SIZE);

return 0;}

6 0

3 years ago