- An isosceles triangle ABC
- AD is a bisector of ∠A
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- By ASA criteria ∆ABD congurant to ∆ADC
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- By CPCT ( corresponding parts of congurant triangle )
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Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:
a) P(between 236 and 281 days)
b) a) P(last between 236 and 296)
c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least 
data lies within k standard deviation of mean.
For k = 2
Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
At x=0 y=6 the y intercept. The rate is -0.25 so the equation is y=6-0.25x. The ordered pair is (x,6-0.25x).
Answer:
(a) Reflection across the y-axis, followed by translation 10 units down
Step-by-step explanation:
Figure 2 is not a reflection across the origin of Figure 1, so neither of the double reflections will map one to the other.
Reflection across the y-axis will put the bottom point at (5, 3). The bottom point on Figure 2 is at (5, -7), so has been translated down by 3-(-7) = 10 units.
Figure 1 is mapped to Figure 2 by reflection over the y-axis and translation down 10 units.
Answer:
y=2x-19
Step-by-step explanation:
I'm guessing you mean slope intercept form y=mx+b
If so, first you would have to find the slope of the line
To do that, use the formula y2-y1/x2-x1
Remember you can pick any coordinate pair for this
I will pick 1=y2 -5=y1 10=x2 and 7=x1
When I put that in the equation I get 1-(-5)/10-7
Overall I get 6/3, or 2
Now to find the y intercept, you plug in the slope and one of the coordinates(any is fine)
I will pick (10,1)
1=y and 10=x and 2=m
1=2(10)+b
this simplifies to 1=20+b
now subtract 20 from both sides and get -19 = b
Now you have your equation y=2x-19
