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2 years ago

15

I don’t understand this at all

1 answer:

xz_007 [3.2K]2 years ago

8 0

Answer:

x=8

Step-by-step explanation:

You would set them equal to each other to get 9x-13=6x+11.

You would them move 6x over so -6x on both sides. This would then get you 3x-13=11.

Then move the -13 over so add 13 to both sides to get 3x=24

Then get x by itself so divide by 3 to get x=24/3.

Then that simplified is 8

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The blue dot is at what value on the number line?<br> +<br> +<br> -7<br> -3

jeka57 [31]

Answer:

there's no picture to see on here

5 0

2 years ago

At 8am,Ming Wei started travelling from Town A to Town B.At 8:40am, Ali started travelling from Town B to Town A.Mingwei's speed

Vesnalui [34]

Let's write some equations.

Mingwei's distance from Town A after $x$ hours from 8:00 is $45x$ .

Ali's distance from Town B after $x$ hours is $30x-20$ , since he doesn't start walking for 40 minutes.

When Mingwei's distance is twice Ali's, they've met up (since their distance from Town A is twice their distance from Town B).

So, this gives $45x=60x-40$ , so $15x=40$ , so $x=\frac{40}{15} = \frac{8}{3}$ , so the time is 10:40.

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7 0

2 years ago

Andrew is paid $4 per hour for the first 30 hours he works each week. He makes $5 per hour for each hour he works over 30 hours

klasskru [66]

Answer:

If Andrew works for 30 for $4 he will have a total wage of 30×4=$120

And gets additional $5for every hr worked beyond 30hrs in that week

So he gets a total of 5(x-30)

So if he works for 40hrs he gets a total wage of

5(40-30)=50

120+50=$170

If he works for 50 hours he gets Total wage of

5(50-30)=100

120+100=$220

4 0

3 years ago

Help please. I need this in a few minutes

Ghella [55]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago