Answer:
1st problem: b) 
2nd problem: c) 
Step-by-step explanation:
1st problem:
The formula/equation you want to use is:
where
t=number of years
A=amount he will owe in t years
P=principal (initial amount)
r=rate
n=number of times the interest is compounded per year t.
We are given:
P=2500
r=12%=.12
n=12 (since there are 12 months in a year and the interest is being compounded per month)
Time to clean up the inside of the ( ).
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2nd Problem:
Compounded continuously problems use base as e.
P is still the principal
r is still the rate
t is still the number of years
A is still the amount.
You are given:
P=2500
r=12%=.12
Let's plug that information in:
.
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
x = 6
Step-by-step explanation:
9 / 6 = (2x - 6) / 4 (by the side splitter theorem)
6(2x - 6) = 36
12x - 36 = 36
12x= 72
x = 6
Since there is two negative signs in the original equation, you need two negative signs in the equivalent one as well.
Because one of the negatives if before the fraction, it doesn't matter if the second negative is on the 13 or on the 12.
The answer is A.
Answer:
<u>The correct answer is B. 150 cm.</u>
Correct statement, question and diagram:
The diagram shows a door that has a window in it. The front faces of the door and window are similar rectangles that have the dimensions shown. What is <em>h, </em>the height of the window in centimeters?
A. 66 cm
B. 150 cm
C. 186 cm
D. Not here.
Source:
Question that can be found at quizizz
Step-by-step explanation:
Let's recall that if the door and the window in it are similar rectangles, then we have:
60/84 = h/210
84 * h = 210 * 60
84h = 12,600
h = 12,600/
h = 150 cm
<u>The correct answer is B. 150 cm.</u>
