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3 years ago

Use the diagram below to find the measured value of x.

Mathematics

1 answer:

dexar [7]3 years ago

5 0

Answer:

They're the same angle. I would look up transversals so you could understand it a bit more. I'll upload a picture of a transversal in my answer but you should search it anyways.

Anyways,

To solve, you set 160 equal to the other side.

160 = 3x + 10

150 = 3x

x = 50

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What is the degree of the polynomial below? 4x^3+3x^2+6x+5 A. 0 B. 3 C. 1 D. 2

alexira [117]

Answer:

B. 3

Step-by-step explanation:

The degree of this polynomial is based on the highest power on the exponents (if there is more than one variable, it is based on the sum)

The highest power is 3, so the degree is 3

6 0

3 years ago

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Please just answer don’t ask

frozen [14]

Answer:

The strawberry is 3, The watermelon is 3, The peach is 9, and the other one is 5

3+3+9+5=20

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3 years ago

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Solve the equation by Completing the Square x2 – 10x + 13 = 0

user100 [1]

Answer:

$x=5+\sqrt{12}$

$x=5-\sqrt{12}$

Step-by-step explanation:

$x^2-10x+13=0$

$x^2-10x=-13$

$x^2-10x+(\frac{10}{2})^2 =-13+(\frac{10}{2})^2$

$x^2-10x+(5)^2=-13+(5)^2$

$x^2-10x+25=-13+25\\x^2-10x+25=12$

Factor.

$(x-5)^2=12$

Extract the square root.

$x-5=\frac{+}{} \sqrt{12}$

Add 5

$x=5+\sqrt{12}$

$x=5-\sqrt{12}$

4 0

3 years ago

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In a survey of 400 seniors, x percent said that they plan on majoring in physics. One university has used this data to estimate

azamat

Answer:

2 percent

Step-by-step explanation:

We can use two separate fractions, one representing the amount of physics majors expected and the amount of seniors expected in physics majors by the university.

$\frac{400x}{66} = \frac{400}{3600}$

Now cross multiply.

$\frac{66*400}{400x * 3600}$

x will be removed.

$\frac{26400}{1320000}$

Simplifying this fraction will get you $\frac{1}{50}$ , which in percentage form, will be 2 percent.

8 0

2 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

6 0

3 years ago