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son4ous [18]
2 years ago
8

Does anyone know what 64.4 as a fraction is?​

Mathematics
2 answers:
klasskru [66]2 years ago
8 0

As a mixed number, it's 64 and 4/10:

      64\frac{4}{10}

As an improper fraction, it's 644/10:

    \dfrac{644}{10}

This can also be reduced to 322/5:

    \dfrac{322}{5}

Tamiku [17]2 years ago
5 0

Answer: 64 \frac{2}{5}

Step-by-step explanation:

=64+0.4

=64+\frac{2}{5}

=64\frac{2}{5}

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) All human blood can be typed as one of O, A, B, or AB. The distribution of the type varies a bit with race. For African-Americ
ivann1987 [24]

Answer:

The correct option is 1 - [(0.8)¹⁰+10*0.2*(0.8)⁹]= 0.6242

Step-by-step explanation:

Hello!

Given the distribution of probabilities for blood types for African-Americans:

O: 0.4

A: 0.2

B: 0.32

AB: 0.08

A random sample of 10 African-American is chosen, what is the probability that 2 or more of them have Type A blood?

Let X represent "Number of African-Americans with Type A blood in a sample of 10.

Then you have two possible outcomes,

"Success" the person selected has Type A blood, with an associated probability p= 0.2

"Failure" the selected person doesn't have Type A blood, with an associated probability q= 0.8

(You can calculate it as "1-p" or adding all associated probabilities of the remaining blood types: 0.4+0.32+0.08)

Considering, that there is a fixed number of trials n=10, with only two possible outcomes: success and failure. Each experimental unit is independent of the rest and the probability of success remains constant p=0.2, you can say that this variable has a Binomial distribution:

X~Bi(n;p)

You can symbolize the asked probability as:

P(X≥2)

This expression includes the probabilities: X=2, X=3, X=4, X=5, X=6, X=7, X=8, X=9, X=10

And it's equal to

1 - P(X<2)

Where only the probabilities of X=0 and X=1 are included.

There are two ways of calculating this probability:

1) Using the formula:

P(X)= \frac{n!}{(n-X)!X!} *p^{x} * q^{n-x}

With this formula, you can calculate the point probability for each value of X=x₀ ∀ x₀=1, 2, 3, 4, 5, 6, 7, 8, 9, 10

So to reach the asked probability you can:

a) Calculate all probabilities included in the expression and add them:

P(X≥2)= P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6) + P(X=7) + P(X=8) + P(X=9) + X=10

b) Use the complement rule and calculate only two probabilities:

1 - P(X<2)= 1 - [P(X=0)+P(X=1)]

2) Using the tables of the binomial distribution.

These tables have the cumulative probabilities listed for n: P(X≤x₀)

Using the number of trials, the probability of success, and the expected value of X you can directly attain the corresponding cumulative probability without making any calculations.

>Since you are allowed to use the complement rule I'll show you how to calculate the probability using the formula:

P(X≥2) = 1 - P(X<2)= 1 - [P(X=0)+P(X=1)] ⇒

P(X=0)= \frac{10!}{(10-)0!0!} *0.2^{0} * 0.8^{10-0}= 0.1074

P(X=1)= \frac{10!}{(10-1)!1!} *0.2^{1} * 0.8^{10-1}= 0.2684

⇒ 1 - (0.1074+0.2684)= 0.6242

*-*

Using the table:

P(X≥2) = 1 - P(X<2)= 1 - P(X≤1)

You look in the corresponding table of n=10 p=0.2 for P(X≤1)= 0.3758

1 - P(X≤1)= 1 - 0.3758= 0.6242

*-*

Full text in attachment.

I hope it helps!

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Read 2 more answers
Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4
Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at (x_1,y_1) and point Q at (x_2,y_2) in the proportion a:b, we use the formula:

x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1

line segment PQ  is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1

4 0
3 years ago
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