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Morgarella [4.7K]
3 years ago
9

Solve for a. a+b= 15

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

So sorry I got it wrong and don't know how to delete

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By selling 20 oranges for#1.35 a trader makes a profit of 8% what is the percentage gain or loss if he sells the same 20 oranges
pav-90 [236]

Answer:

  12% loss

Step-by-step explanation:

The selling price is the sum of the cost price and the markup. Here, the markup (profit) is expressed as a percentage of the cost price.

<h3>Cost price</h3>

The relation between selling price and cost price is ...

  selling price = cost price + cost price × markup fraction

  selling price = cost price × (1 + markup fraction)

Then the original cost price is ...

  cost price = (selling price) / (1 + markup fraction)

  cost price = #1.35 / (1 +8%) = #1.25

<h3>Profit</h3>

After the change in selling price, we can find the markup fraction (profit rate) to be ...

  1 + markup fraction = (selling price)/(cost price)

  markup fraction = (selling price)/(cost price) -1

  markup fraction = #1.10/1.25 -1 = 0.88 -1 = -0.12

The trader has a 12% loss when selling the oranges at #1.10.

 

6 0
2 years ago
Line all is bisecting segment AC. Find AC when AB = 6x - 7 and BC = 2x + 3
marin [14]

Answer:

AC = 8x - 4

Step-by-step explanation:

AC = AB + BC

AC = 6x - 7 + 2x + 3

AC = 6x + 2x - 7 + 3

AC = 8x - 4

3 0
3 years ago
3<br><img src="https://tex.z-dn.net/?f=%203%5Cfrac%7B4%7D%7B5%7D%20%20%5Cdiv%20%203%5Cfrac%7B1%7D%7B6%7D%20" id="TexFormula1" ti
Jobisdone [24]
Hey There!

Here is your answer:

First write the equation down:

-3 4/5 ÷ -3 1/6

Then put the mixed fractions into whole numbers:

-3 4/5= 5×-3=-15+4=-11= -11/5
&
-3 1/6= 6×-3=-18+1=-17= -17/6

Now right the new problem:

-11/5×6/-17

Now multiply:

-11×6=-66
5×-17=-85

Which means -66/-85 is your answer!

Hope this helps!
3 0
3 years ago
Which of these consumers might depend on a rabbit for its energy?
olga nikolaevna [1]

Answer:

coyote

Step-by-step explanation:

6 0
3 years ago
There are 28 students in Sharon's class. One-fourth of the students were absent on Monday. How many students were present on Mon
PIT_PIT [208]

21 students

You find this by subtracting the number of students absent from the total amount of students in the class 28-(28*\frac{1}{4} )=21.

8 0
3 years ago
Read 2 more answers
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